我有一个界面
interface Dot
{
// protected Random r = new Random();
void createdot(Rectangle clientrectangle, Control.ControlCollection Controls);
}
我将此接口用作我所声明的派生类的基类
public class BlueDot : Dot
{
public List<Label> bluedot = new List<Label>();
Random r = new Random();
public void createdot(Rectangle ClientRectangle, Control.ControlCollection Controls)
{
for (int i = 0; i < 5; i++)
{
var temp = new Label();
temp.Location = new Point(r.Next(ClientRectangle.Right - 10), r.Next(ClientRectangle.Bottom - 20));
temp.Text = "?";
temp.Width = 10;
temp.Height = 10;
temp.ForeColor = System.Drawing.Color.Blue;
temp.BackColor = System.Drawing.Color.White;
Controls.Add(temp);
temp.Visible = true;
temp.Show();
bluedot.Add(temp);
}
}
}
和
public class RedDot:Dot
{
public List<Label> reddot = new List<Label>();
Random r = new Random();
public void createdot(Rectangle Clientrectangle,Control.ControlCollection Controls)
{
for (int z = 0; z < 10; z++)
{
var temp2 = new Label();
temp2.Location = new Point(r.Next(Clientrectangle.Right - 10), r.Next(Clientrectangle.Bottom - 20));
temp2.Text = "?";
temp2.Width = 10;
temp2.Height = 10;
temp2.ForeColor = System.Drawing.Color.Red;
temp2.BackColor = System.Drawing.Color.White;
Controls.Add(temp2);
temp2.Show();
reddot.Add(temp2);
}
}
他们在这里被称为
BlueDot bdot = new BlueDot();
RedDot rdot = new RedDot();
private void Form1_Load(object sender, EventArgs e)
{
this.Activate();
bdot.createdot(this.ClientRectangle,this.Controls);
rdot.createdot(this.ClientRectangle, this.Controls);
}
为什么即使循环执行10次迭代,我仍然只获得5个红点?
这里是示例输出https://www.facebook.com/photo.php?fbid=2372861522202&set=a.1600508493859.85328.1270463960&type=1,我只是无法弄清楚其他5个红点发生了什么,它应该是10个红点....
答案 0 :(得分:2)
这里没有继承问题。问题是随机数生成器。
在您的代码中尝试以下行:
temp2.Location = new Point(10 * z, 10 * z);
更换
temp2.Location = new Point(r.Next(Clientrectangle.Right - 10), r.Next(Clientrectangle.Bottom - 20));
你会看到你的5个蓝色“?” - 标签和你的10个红色“?” - 标签
要解决弱随机数生成器的问题,请尝试播种您的随机数生成器。示例:
Random r = new Random((int)DateTime.Now.Ticks);
答案 1 :(得分:0)
我不确定,但为什么不让你的temp2可见????
temp2.Visible =真
如果此功能不起作用,您可以提供两个输出的屏幕截图。有时由于窗口的大小,一个点可能位于另一个点上。我的意思是他们实际重叠。查看输出可能有助于解决您的问题