iPhone字典中的问题?

时间:2011-09-07 09:02:39

标签: iphone ios ipad nsdictionary

在围绕数组和词典进行游戏时,我正在解决iPhone中的一个小问题。我有和以下数据的产品词典

  name = Product;
    options =     (
                {
            code = code1;
            name = "product AAA";
        },
                {
            code = code1;
            name = "product BBB";
        },
                {
            code = "code2";
            name = "product BBB";
        },
                {
            code = "code3";
            name = "product CCC";
        },
                {
            code = "code3";
            name = "product DDD";
        },
                {
            code = code4;
            name = "product EEE";
        },
                {
            code = code4;
            name = "product FFF";
        }
    );

我也有一系列匹配产品

matchingProducts
{
    "product BBB",
    "product CCC",
    "product DDD"
)

现在,我想要做的就是我想从productsProducts数组中删除产品字典。我该怎么做。 注意:根据我的业务规则,我无法使用密钥删除对象。我有问题,因为我有重复名称,但我必须得到最终结果字典,如下所示。可能吗。

   name = Product;
    options =     (
                {
            code = code1;
            name = "product AAA";
        },
                {
            code = code1;
            name = "product BBB";
        },
                {
            code = code4;
            name = "product EEE";
        },
                {
            code = code4;
            name = "product FFF";
        }
    );

如果我的问题不明确,请回​​复我。

我使用下面的代码修复了java中的类似问题

for (int j = 0; j < matchingProducts.size(); j++) {
 String product = ((Product) matchingProducts.elementAt(i)).name;

 for (int i = 0; i <Product.size(); i++) {
     String productName = ((Product) Product.elementAt(i)).name;
     if (product.equals(productName)) {
  Product.removeElementAt(i);
  break;
     }
 }
 }

1 个答案:

答案 0 :(得分:1)

NSMutableDictionary *Product = initialize like you did with Products;
NSMutableDictionary *resultant = [NSMutableDictionary alloc]init]; //this will have your result    
NSArray *keys = [Product allKeys];
for(int i = 0 ; i < [keys count]; i++)
  {
    id temp = [Product objectForKey:keys[i]];

 bool matchFound = NO;
for (int j = 0; j < [matchingProduct count]; j++)
   {
     id temptemp = [matchingProduct objectAtIndex:j] //Assuming matchingProduct is an NSArray or NSMutableArray
     if(temp == temptemp)
       {
           matchFound = YES;
       }
   }

  if(!matchFound)
     [resultant addObject:temp];     

}

//结果现在有你想要的。使用它。