我正在制作短信应用，想要访问我的Android应用中的联系人
我想访问联系人，就像他们在实际联系人列表中的位置一样。选择后，我需要返回到我可以向该人发送短信的活动。或者是否可以访问存储联系人的数据库？
我的代码如下所示：
String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
String name = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
String no = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));
我的LogCat看起来像这样：
09-07 12:46:15.458: DEBUG/AndroidRuntime(473): Shutting down VM
09-07 12:46:15.458: WARN/dalvikvm(473): threadid=1: thread exiting with uncaught exception (group=0x40015560)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): FATAL EXCEPTION: main
09-07 12:46:15.478: ERROR/AndroidRuntime(473): java.lang.RuntimeException: Failure delivering result ResultInfo{who=null, request=0, result=-1, data=Intent { dat=content://com.android.contacts/contacts/lookup/0r1-512D3F3D533B/1 flg=0x1 (has extras) }} to activity {task.list/task.list.Msgactivity}: java.lang.IllegalArgumentException: column 'data1' does not exist
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.ActivityThread.deliverResults(ActivityThread.java:2532)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.ActivityThread.handleSendResult(ActivityThread.java:2574)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.ActivityThread.access$2000(ActivityThread.java:117)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:961)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.os.Handler.dispatchMessage(Handler.java:99)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.os.Looper.loop(Looper.java:123)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.ActivityThread.main(ActivityThread.java:3683)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at java.lang.reflect.Method.invokeNative(Native Method)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at java.lang.reflect.Method.invoke(Method.java:507)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at dalvik.system.NativeStart.main(Native Method)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): Caused by: java.lang.IllegalArgumentException: column 'data1' does not exist
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.database.AbstractCursor.getColumnIndexOrThrow(AbstractCursor.java:314)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.database.CursorWrapper.getColumnIndexOrThrow(CursorWrapper.java:99)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at task.list.Msgactivity.onActivityResult(Msgactivity.java:99)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.Activity.dispatchActivityResult(Activity.java:3908)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): at android.app.ActivityThread.deliverResults(ActivityThread.java:2528)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): ... 11 more
09-07 12:46:15.489: WARN/ActivityManager(61): Force finishing activity task.list/.Msgactivity
任何人都可以帮助我吗？
答案 0 :(得分：13)
使用此代码选择联系人：
Button button = (Button)findViewById(R.id.pickcontact);
button.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View v)
{
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);
}
});
@Override public void onActivityResult(int reqCode, int resultCode, Intent data){ super.onActivityResult(reqCode, resultCode, data);
switch(reqCode)
{
case (PICK_CONTACT):
if (resultCode == Activity.RESULT_OK)
{
Uri contactData = data.getData();
Cursor c = managedQuery(contactData, null, null, null, null);
if (c.moveToFirst())
{
String id = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
String hasPhone =
c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (hasPhone.equalsIgnoreCase("1"))
{
Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,null, null);
phones.moveToFirst();
String cNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
// Toast.makeText(getApplicationContext(), cNumber, Toast.LENGTH_SHORT).show();
setCn(cNumber);
}
}
}
}
}
答案 1 :(得分：7)
检查以下链接：
How to call Android contacts list?
How to get contacts from native phonebook in android
How to obtain all details of a contact in Android
How to get the first name and last name from Android contacts?
How to import contacts from phonebook to our application
How to get all android contacts but without those which are on SIM
http://mobile.tutsplus.com/tutorials/android/android-essentials-using-the-contact-picker/
答案 2 :(得分：2)
试试这段代码。这将存储ArrayList中的所有联系人
ArrayList<HashMap<String,String>> contactData=new ArrayList<HashMap<String,String>>();
ContentResolver cr = getContentResolver();
Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
while (cursor.moveToNext()) {
try{
String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
String name=cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null);
while (phones.moveToNext()) {
String phoneNumber = phones.getString(phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER));
HashMap<String,String> map=new HashMap<String,String>();
map.put("name", name);
map.put("number", phoneNumber);
contactData.add(map);
}
phones.close();
}
}catch(Exception e){}
}
如果要存储特定联系人，请使用if条件。
答案 3 :(得分：0)
我可以使用@ Balaji.K的示例进行一些修改。我遇到的主要问题是
while (cursor.moveToNext()) {
将跳过第一个结果。
我还想建立一个电话号码列表，供用户选择，如果没有一个都标记为“移动”。我还输入了要搜索的名称（在此示例中用变量替换），但是可以修改此代码以通过将null替换为“ selection”和“ selection_args”，并像我所做的那样遍历“ contacts”中的所有内容来构建集合“电话”。这是我最后的结果（在Kotlin中）：
val selection = "lower(${ContactsContract.Contacts.DISPLAY_NAME_PRIMARY}) LIKE ?"
val selectionArgs = arrayOf("<SEARCH_TERM>")
selectionArgs[0] = "%<SEARCH_TERM>%"
// Query contacts for someone with a matching name
val contacts = contentResolver.query(ContactsContract.Contacts.CONTENT_URI,
null, selection, selectionArgs, null)
contacts!!.moveToFirst()
if (contacts.count > 1) {
// TODO: Disambiguate and move to the correct position
}
val contactId = contacts.getString(contacts.getColumnIndex(
ContactsContract.Contacts._ID))
// Check if contact has at least one phone number
if (contacts.getString(contacts.getColumnIndex(
ContactsContract.CommonDataKinds.Phone.HAS_PHONE_NUMBER)) == "1") {
val sel = "${ContactsContract.CommonDataKinds.Email.CONTACT_ID} = ?"
val selArgs = arrayOf(name)
val sort = "${ContactsContract.CommonDataKinds.Email.LAST_TIME_CONTACTED} DESC"
selArgs[0] = contactId
val phones = contentResolver.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, sel, selArgs, sort)
phones!!.moveToFirst()
// Iterate through phone numbers if multiple
if (phones.count > 1) {
val phoneNumbers = mutableMapOf<Int, ContactData>()
var loop = true
var mobileIndex: Int? = null
while (loop) {
val phoneType = phones.getInt(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE))
val phoneName = ContactsContract.CommonDataKinds.Phone.getTypeLabel(resources, phoneType, null).toString()
phoneNumbers[phones.position] = ContactData(phoneName, phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)))
// Remember what position the mobile number was in
if (phoneType == ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE) {
mobileIndex = phones.position
}
loop = phones.moveToNext()
}
phones.moveToPosition(mobileIndex)
}
}