Question

HttpRequest httpReq=new DefaultHttpRequest(HttpVersion.HTTP_1_1,HttpMethod.POST,uri);
httpReq.setHeader(HttpHeaders.Names.HOST,host);
httpReq.setHeader(HttpHeaders.Names.CONNECTION,HttpHeaders.Values.KEEP_ALIVE);
httpReq.setHeader(HttpHeaders.Names.ACCEPT_ENCODING,HttpHeaders.Values.GZIP);
String params="a=b&c=d";
ChannelBuffer cb=ChannelBuffers.copiedBuffer(params,Charset.defaultCharset());
httpReq.setHeader(HttpHeaders.Names.CONTENT_LENGTH,cb.readableBytes());
httpReq.setContent(cb);

不会产生有效请求。发送发布请求的正确方法是什么，最好是手动构建参数数据而不是使用DataFactory。另外，为什么HttpDataFactory不包含在任何版本中？

Answer 1

你写的一切都是正确的，只需添加httpReq.setHeader(HttpHeaders.Names.CONTENT_TYPE,"application/x-www-form-urlencoded"); 你的例子会奏效。对于更复杂的代码，您需要添加url编码。

Answer 2

DefaultFullHttpRequest request = new DefaultFullHttpRequest(HttpVersion.HTTP_1_1, HttpMethod.POST, uri.toASCIIString());
request.headers().set(HttpHeaders.Names.HOST, ip);
request.headers().set(HttpHeaders.Names.CONTENT_TYPE,"application/x-www-form-urlencoded");
List<NameValuePair> nvps = new ArrayList<NameValuePair>();
nvps.add(new BasicNameValuePair(param.getKey(), param.getValue()));
HttpEntity httpEntity = new UrlEncodedFormEntity(nvps);
ByteBuf byteBuf = 
Unpooled.copiedBuffer(EntityUtils.toByteArray(httpEntity));
request.content().writeBytes(byteBuf);
request.headers().set(HttpHeaders.Names.CONTENT_LENGTH,request.content().readableBytes());
fu.channel().writeAndFlush(request)

使用Netty发送POST参数，为什么版本中没有DefaultHttpDataFactory？

2 个答案: