我有这个代码可以获取页面的HTML源代码:
$page = file_get_contents('http://example.com/page.html');
$page = htmlentities($page);
我想从中搜集一些内容。例如,假设页面的源包含:
<strong>technorati.com</strong><br />
Connection failed<br /><br />Pinging <strong>icerocket.com</strong><br />
Connection failed<br /><br />Pinging <strong>weblogs.com</strong><br />
Done<br /><br />Pinging <strong>newsgator.com</strong><br />
Done<br /><br />Pinging <strong>blo.gs</strong><br />
Done<br /><br />Pinging <strong>feedburner.com</strong><br />
Done<br /><br />Pinging <strong>blogstreet.com</strong><br />
Done<br /><br />Pinging <strong>my.yahoo.com</strong><br />
Connection failed<br /><br />Pinging <strong>moreover.com</strong><br />
Connection failed<br /><br />Pinging <strong>newsisfree.com</strong><br />
Done<br />
有没有办法可以从源代码中删除它并将其存储在变量中,所以它看起来像这样:
technorati.com 连接失败
icerocket.com 连接失败
eblogs.com 完成
等。
原因是页面是动态的,这就是我遇到问题的原因。我可以搜索源中的每个站点吗?但那我怎么得到它之后的结果呢? (连接失败/完成)
非常感谢您的帮助!
答案 0 :(得分:15)
我尝试使用简单的HTML DOM PHP库抓取多个网站,可以在此处获取:http://simplehtmldom.sourceforge.net/
然后使用这样的代码:
<?php
include_once 'simple_html_dom.php';
$url = "http://slashdot.org/";
$html = file_get_html($url);
//remove additional spaces
$pat[0] = "/^\s+/";
$pat[1] = "/\s{2,}/";
$pat[2] = "/\s+\$/";
$rep[0] = "";
$rep[1] = " ";
$rep[2] = "";
foreach($html->find('h2') as $heading) { //for each heading
//find all spans with a inside then echo the found text out
echo preg_replace($pat, $rep, $heading->find('span a', 0)->plaintext) . "\n";
}
?>
这导致类似:
5.8 Earthquake Hits East Coast of the US
Origins of Lager Found In Argentina
Inside Oregon State University's Open Source Lab
WebAPI: Mozilla Proposes Open App Interface For Smartphones
Using Tablets Becoming Popular Bathroom Activity
The Syrian Government's Internet Strategy
Deus Ex: Human Revolution Released
Taken Over By Aliens? Google Has It Covered
The GIMP Now Has a Working Single-Window Mode
Zombie Cookies Just Won't Die
Motorola's Most Important 18 Patents
MK-1 Robotic Arm Capable of Near-Human Dexterity, Dancing
Evangelical Scientists Debate Creation Story
Android On HP TouchPad
Google Street View Gets Israeli Government's Nod
Internet Restored In Tripoli As Rebels Take Control
GA Tech: Internet's Mid-Layers Vulnerable To Attack
Serious Crypto Bug Found In PHP 5.3.7
Twitter To Meet With UK Government About Riots
EU Central Court Could Validate Software Patents
答案 1 :(得分:0)
这不是最好的解决方案,但它有效:
$page = file_get_contents('http://example.com/page.html');
preg_match_all('#<strong>([^<]+)</strong><br />\s*([^<]+)<#', $page,
$result, PREG_SET_ORDER);
foreach ($result as $row) {
echo "<p><b>$row[1]</b> $row[2]</p>\n";
}
如果需要更复杂的事情,请考虑DOMDocument。
答案 2 :(得分:-3)