如何在Listview中按字母顺序显示联系人

时间:2011-09-06 08:08:53

标签: android alphabetical

我有自定义列表视图,我需要按字母顺序显示联系人你可以提供示例代码我该如何实现?

4 个答案:

答案 0 :(得分:40)

答案 1 :(得分:2)

你需要这样做:

Cursor cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");

答案 2 :(得分:0)

使用此代码检索联系人

ArrayList<HashMap<String,String>> contactData=new ArrayList<HashMap<String,String>>();
ContentResolver cr = getContentResolver();
     Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
     while (cursor.moveToNext()) {
         try{
         String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID)); 
         String name=cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
         String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 
         if (Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
             Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null);
             while (phones.moveToNext()) { 
                 String phoneNumber = phones.getString(phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER));
                 HashMap<String,String> map=new HashMap<String,String>();
                 map.put("name", name);
                 map.put("number", phoneNumber);
                 contactData.add(map);
             } 
             phones.close(); 
         }
     }catch(Exception e){}
     }

现在,联系人详细信息存储在 contactData ArrayList中。现在将此arrayList排序为bellow

Collections.sort(contactData, new Comparator(){
                @Override
                public int compare(Object o1, Object o2) {
                    HashMap map1=(HashMap)o1;
                    HashMap map2=(HashMap)o2;
                    String s1=(String)map1.get("name");
                    String s2=(String)map2.get("name");
                    return s1.compareTo(s2);
                }
            });

现在,联系人详细信息存储在 contactData ArrayList中的排序顺序中。

答案 3 :(得分:0)

我已将字母标题添加到联系人列表

new ReadContactTask(context, showProgressDialog,new OnContactReadListener() {
            @Override
            public void onContactRead(List<ContactItem> dummyList) {

                ArrayList<ContactItem> latestPhoneContacts = new ArrayList<>();

                if(dummyList!=null && dummyList.size()>0)
                {
                    tvNoResult.setVisibility(View.GONE);

                    for(ContactItem contactItem : dummyList){
                        String contactNameInCapital = "";
                        if(contactItem.getContactName()!=null && contactItem.getContactName().length()>2){
                            contactNameInCapital = contactItem.getContactName().substring(0,1).toUpperCase();

                            if(contactNameInCapital.charAt(0) != previousContact.charAt(0))
                            {
                                latestPhoneContacts.add(new ContactItem(contactNameInCapital.substring(0,1)));
                                latestPhoneContacts.add(contactItem);
                            }
                            else
                            {
                                latestPhoneContacts.add(contactItem);
                            }

                            previousContact = contactNameInCapital;
                        }
                    }
                    if(latestPhoneContacts!=null && latestPhoneContacts.size()>0)
                        contactListAdapter.addItems(latestPhoneContacts);
                }
            }

            @Override
            public void onContactEmpty() {

            }
        }).execute();

其中

private String previousContact ="Zee";