我想序列化这个课程:
[Serializable]
[XmlRoot(ElementName = "Rates")]
public class CbrRate : IRate
{
public CbrRate()
{
}
public CbrRate(DateTime date, ICurrency currency, decimal rate)
{
Currency = currency;
Date = date;
Rate = rate;
}
[XmlIgnore]
public string SrcName
{
get { return "CBR"; }
}
[XmlElement(ElementName = "RequestDate")]
public DateTime Date { get; set; }
[XmlIgnore]
public ICurrency Currency { get; set; }
[XmlElement(ElementName = "Direction")]
public string Direction
{
get { return "RUR=>" + CodeChar.Trim(); }
}
[XmlElement(ElementName = "RateValue")]
public decimal Rate { get; set; }
[XmlElement(ElementName = "RateBase")]
public decimal BaseRate
{
get { return Math.Round(Rate/Nominal, 4); }
}
[XmlElement(ElementName = "RateCross")]
public decimal CrossRate
{
get { return Math.Round(1.00M/BaseRate, 4); }
}
[XmlElement(ElementName = "CodeNum")]
public int CodeNum
{
get { return Currency.CodeNumIso; }
}
[XmlElement(ElementName = "CodeISO")]
public string CodeChar
{
get { return Currency.CodeCharIso; }
}
[XmlElement(ElementName = "CurrencyName")]
public string Name
{
get { return Currency.Name; }
}
[XmlElement(ElementName = "Nominal")]
public decimal Nominal
{
get { return Currency.Nominal; }
}
}
public static XDocument Serialize<T>(this T source)
{
var target = new XDocument();
var s = new XmlSerializer(typeof (T));
using (var writer = target.CreateWriter())
{
s.Serialize(writer, source);
writer.Close();
}
return target;
}
但是,我有:
<?xml version="1.0" encoding="utf-16"?>
<ArrayOfCbrRate xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<CbrRate>
<RequestDate>2011-09-05T18:49:55.1195696+04:00</RequestDate>
<RateValue>31.0539</RateValue>
</CbrRate>
...
如何创建正确的xml,如下所示:
<ArrayOfRates>
<Rates>
<RequestDate></RequestDate>
<Direction></Direction>
<RateValue></RateValue>
<RateBase></RateBase>
...
答案 0 :(得分:1)
因此,假设您正在序列化List<CbrRate >
,您需要为列表创建一个包装类,以便根据需要对其进行序列化。像这样:
[XmlRoot("root")]
public class ListOfRates
{
[XmlArray("ArrayOfRates")]
[XmlArrayItem("Rate")]
public List<CbrRate> Rates { get; set; }
}
这将产生你想要的xml。或者你可以稍微使用属性,但如果你不想拥有根:
[XmlRoot("ArrayOfRates")]
public class ListOfRates
{
[XmlArrayItem("Rate")]
public List<CbrRate> Rates { get; set; }
}
这两个属性XmlArray
和XmlArrayItem
是关键所在。如果没有为xml元素提供名称,则默认为属性名称。
答案 1 :(得分:1)
首先,.Net XmlSerializer只会序列化读/写属性(或字段)。这就是为什么只有RequestDate
和RateValue
被序列化的原因。
为了实现你提到的XML结构,你需要像Roel所说的那样创建一个包装类。