Question

如何在android中分配资源ID？我使用aapt dump resources浏览正常的应用程序资源：

Package Groups (1)
Package Group 0 id=127 packageCount=1 name=com.android.picker
  Package 0 id=127 name=com.android.picker typeCount=5
    type 0 configCount=0 entryCount=0
    type 1 configCount=1 entryCount=7
      spec resource 0x7f020000 com.android.picker:drawable/btn_normal: flags=0x00000000
      spec resource 0x7f020001 com.android.picker:drawable/icon: flags=0x00000000
      spec resource 0x7f020002 com.android.picker:drawable/icon1: flags=0x00000000
.......

从上面的消息中，我发现资源id以127（0x7f）开头。我浏览另一个应用程序资源：

Package Groups (1)
Package Group 0 id=2 packageCount=1 name=com.android.pinkskin
  Package 0 id=2 name=com.android.pinkskin typeCount=6
    type 0 configCount=0 entryCount=0
    type 1 configCount=1 entryCount=7
      spec resource 0x02020000 com.android.pinkskin:drawable/btn_default: flags=0x00000000
      spec resource 0x02020001 com.android.pinkskin:drawable/btn_default_normal: flags=0x00000000
      spec resource 0x02020002 com.android.pinkskin:drawable/btn_default_normal_disable: flags=0x00000000
      spec resource 0x02020003 com.android.pinkskin:drawable/btn_default_normal_disable_focused: flags=0x00000000
.........

两个应用程序之间的区别在于它们的make文件： com.android.picker make文件是：

LOCAL_PATH:= $(call my-dir)
include $(CLEAR_VARS)

LOCAL_MODULE_TAGS := optional

LOCAL_SRC_FILES := $(call all-java-files-under, src)

LOCAL_PACKAGE_NAME := Picker


include $(BUILD_PACKAGE)

和com.android.pinkskin应用程序的make文件是：

LOCAL_PATH:= $(call my-dir)
include $(CLEAR_VARS)

LOCAL_MODULE_TAGS := optional

LOCAL_SRC_FILES := $(call all-java-files-under, src)

LOCAL_PACKAGE_NAME := PiknSkin
LOCAL_AAPT_FLAGS := -x

LOCAL_EXPORT_PACKAGE_RESOURCES := true

include $(BUILD_PACKAGE)

我找到了Android resource id always have a package identifier, so their value cannot be 0. – Romain Guy。谁可以解释一下？

如何在android中分配资源ID？

0 个答案: