/* Adding Experiences */
$("#addExperience").click(function () {
if(experiencectr>5){
alert("WOW! But 5 experiences are enough.");
return false;
}
var newTextBoxDiv = $(document.createElement('div'))
.attr("id", 'ExperienceDiv' + experiencectr);
newTextBoxDiv.html('<label>Experience No. '+ experiencectr + ' : </label>' +
'<input type="text" name="experience[]" id="experience' + experiencectr + '" > ' +
'<input type="text" id="year' + experiencectr +
'" size="5" name="years[]"><label>years</label>');
newTextBoxDiv.appendTo("#ExperienceBoxesGroup");
experiencectr++;
});
在上面的代码中,它添加了两个字段:经验和年份文本字段
foreach ($_POST['experience'] as $experience) {
// save $experience to database
$sql_experience = "INSERT INTO experiences(number,experience)
values ('$number','$experience')";
if($result3 = mysql_query($sql_experience ,$db))
{
foreach ($_POST['years'] as $years) {
$sql_years = "UPDATE experiences SET years=$years WHERE experience=$experience";
if($result = mysql_query($sql_years ,$db))
{ }
else
{ echo "ERROR: ".mysql_error(); }
}
}
else
{ echo "ERROR: ".mysql_error(); }
}
在上面的代码中,它保存到数据库中,但字段列在所有行中都具有SAME值。你能帮帮我吗?
我需要一个答案:D
答案 0 :(得分:1)
您必须获取索引才能访问其他数组中的值:
foreach($_POST['experiences'] as $idx => $experience) {
$sql = "INSERT INTO experiences (number, experience, years)
VALUES ({$idx}, {$experience}, {$_POST['years'][$idx]}");
// execute query, etc
}
这会有效,但您可能不应该这样做,因为它让您对SQL injections开放。更好的方法是清理输入(例如:mysql_reaL_escape_string
或其mysqli等价物)
最好的方法是using prepared statements:
$stmt = $dbh->prepare("INSERT INTO experiences (number, experience, years)
VALUES (?, ?, ?)");
foreach($_POST['experiences'] as $idx => $experience) {
// pass values and execute
$stmt->execute(array($idx, $experience, $_POST['years'][$idx]));
}