Question

我有一个数组，其中包含来自数据库的一组信息，但其中一些是重复的，在更改的数组的最深部分只有1个值。例如：

[0] => Array( ['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff" )
[1] => Array( ['id'] => 2 , ['name'] => "Second Array" , ['more'] => "stuff1" )
[2] => Array( ['id'] => 2 , ['name'] => "Second Array" , ['more'] => "stuff2" )
[3] => Array( ['id'] => 3 , ['name'] => "Third Array" , ['more'] => "stuff3" )
[4] => Array( ['id'] => 3 , ['name'] => "Third Array" , ['more'] => "stuff4" )

我要做的是将具有相同['id']字段的任何数组放入具有数组而不是['more']的数组中。例如：

[0] => Array( ['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff" )
[1] => Array( ['id'] => 2 , ['name'] => "Second Array" , ['more'] => Array( [0] => "stuff1" , [1] => "stuff2" ) )
[2] => Array( ['id'] => 2 , ['name'] => "Third Array" , ['more'] => Array( [0] => "stuff3" , [1] => "stuff4" ) )

我试过这几种方法，但我能得到的最接近的函数是将所有['more']值放入1个数组中：

[0] => Array( ['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff" )
[1] => Array( ['id'] => 2 , ['name'] => "Second Array" , ['more'] => Array( [0] => "stuff1" , [1] => "stuff2" , [2] => "stuff3" , [3] => "stuff4" ) )

这是来自这个功能：

<?php
private function compress_duplicates( $a = array() ) {
    $diff_key = array_diff_key( $a , array_unique( $a ) );
    $first_key = array_shift(array_keys($diffkey));
    $array["id"] = $diff_key[$first_key]["id"];
    $array["name"] = $diff_key[$first_key]["name"];
    foreach($diff_key as $term) {
        $array["more"][] = $term["more"];
    }
    return $array;
}
?>

基本上我要问的是：如何在多维数组中找到重复项，然后将每个重复项放入自己的数组中？

Answer 1

$result = array();
foreach ($array as $elem) {
    if (isset($result[$elem['id']])) {
        $result[$elem['id']]['more'] = array_merge((array)$result[$elem['id']]['more'],
                                                   array($elem['more']));
    } else {
        $result[$elem['id']] = $elem;
    }
}

如果要重置$result = array_values($result)数组的键，可选择后跟$result。

PHP从多维数组中查找值，然后将它们放在数组中

1 个答案: