Question

如果由于某种原因我想重复相同的迭代，我怎么能在python中做到这一点？

for eachId in listOfIds:
    #assume here that eachId conatins 10
    response = makeRequest(eachId) #assume that makeRequest function request to a url by using this id
    if response == 'market is closed':
       time.sleep(24*60*60) #sleep for one day

现在当功能在一天之后从睡眠状态唤醒（市场（货币交易市场）开启）我想从eachId = 10 not从eachId = 11恢复我的for循环，因为eachId = 10尚未处理为market was closed，我们非常感谢任何帮助。

Answer 1

这样做：

for eachId in listOfIds:
    successful = False
    while not successful:        
        response = makeRequest(eachId)
        if response == 'market is closed':
            time.sleep(24*60*60) #sleep for one day
        else:
            successful = True

你问题的标题是线索。重复是通过迭代实现的，在这种情况下，您只需使用嵌套的while即可。

Answer 2

使用while循环？

counter = 0
while counter < len(listOfIds):
  # do processing
  counter = counter + 1

如果你得到'市场关闭'，就不要增加。

Answer 3

for eachId in listOfIds:
    while makeRequest(eachId) == 'market is closed':
       time.sleep(24*60*60) #sleep for one day

正如@David所说，如果您不需要捕获response。

Answer 4

i = 0
while i < len(listOfIds):
    eachId = listOfIds[i]
    #assume here that eachId conatins 10
    response = makeRequest(eachId) #assume that makeRequest function request to a url by using this id
    if response == 'market is closed':
       time.sleep(24*60*60) #sleep for one day
    else:
       i += 1

重复for循环的迭代

4 个答案: