excel vba-提取2个字符之间的文本

时间:2011-09-03 13:41:43

标签: excel vba excel-vba scripting

如果我有这个专栏:

ColA
-----
NUMBER(8,3)
NUMBER(20)

我需要一个VBA函数(注意这些开始和结束字符串只会在单元格中出现一次):

extract_val(细胞,start_str,end_str)

即。 extract_val(A1,“(”,“)”)并给出结果:

8,3
20

我只需要在其他vba代码中使用此功能,而不是将其作为公式放在工作表上。

更新(感谢答案,我决定:)

---------------------------
Public Function extract_value(str As String) As String
Dim openPos As Integer
Dim closePos As Integer
Dim midBit As String
 On Error Resume Next
openPos = InStr(str, "(")
 On Error Resume Next
closePos = InStr(str, ")")
 On Error Resume Next
midBit = mid(str, openPos + 1, closePos - openPos - 1)
If openPos <> 0 And Len(midBit) > 0 Then
extract_value = midBit
Else
extract_value = "F"
End If
End Function

Public Sub test_value()
MsgBox extract_value("NUMBER(9)")
End Sub

4 个答案:

答案 0 :(得分:19)

您可以使用instr在字符串中查找字符(例如,返回'('的位置)。然后,您可以使用mid使用'('')'的位置提取子位。

像(来自记忆):

dim str as string
dim openPos as integer
dim closePos as integer
dim midBit as string

str = "NUMBER(8,3)"
openPos = instr (str, "(")
closePos = instr (str, ")")
midBit = mid (str, openPos+1, closePos - openPos - 1)

如果字符串中没有出现这些字符,您可能需要添加错误检查。

答案 1 :(得分:1)

If the string is “Value of A is [1.0234] and Value of B is [3.2345]”

If you want to extract the value of B i.e., 3.2345, then

firstDelPos = InStrRev(textline, “[“) ‘ position of start delimiter
secondDelPos = InStrRev(textline, “]”) ‘ position of end delimiter

stringBwDels = Mid(textline, firstDelPos + 1, secondDelPos – firstDelPos – 1) ‘ extract the string between two delimiters

MsgBox (stringBwDels) ‘ message shows string between two delimiters

答案 2 :(得分:0)

我知道此问题已被标记为已回答,但是我想我将根据更新后的问题的功能添加代码。我做了一个函数,可以解析多个函数。

Sub testextract()
 s = extract_values("This is [what i want to keep][And this]")
 Debug.Print (s)
  End Sub
 Function extract_values(str As String, Optional openStr = "[", Optional closeStr = "]") As String
 Dim openPos As Integer
 Dim closePos As Integer
 Dim midBit As String
 prevOpen = 1
 prevClose = 1
 Dim keep As String
 While prevOpen <> 0
    On Error Resume Next
    openPos = InStr(prevOpen, str, openStr)
    On Error Resume Next
   closePos = InStr(prevClose, str, closeStr)
    On Error Resume Next
    midBit = Mid(str, openPos + 1, closePos - openPos - 1)
    If openPos <> 0 And Len(midBit) > 0 Then
    keep = keep & openStr & midBit & closeStr
   End If
   If openPos = 0 Or prevClose = 0 Then
       i = 0
   Else
      i = 1
  End If
  prevOpen = openPos + i
   prevClose = closePos + i
 Wend
 extract_values = keep
 End Function

答案 3 :(得分:-1)

如果我在一个单元格中有一个黄瓜表作为测试数据,并且需要在第4个管道和第5个管道之间访问“ Header 1”(标题1)下的值,则下面是我的处理方法。我的表格示例在单元格D7中如下所示:

*单元格D7:

enter image description here

代码以访问在'|'第4次出现后找到的'abcd'并且在第5次出现“ |”之前

Dim sheet5 As Worksheet
Dim i As Integer
Dim k As Integer
Dim openPos As Long
Dim clsPos As Long
Dim textBetween as String

'Using for loop to find 4th occurrence of pipe '|' for openPos
For i = 1 To 4
openPos = InStr(openPos + 1, sheet5.Range("D7"), "|", vbTextCompare)
Next i

'Using for loop to find 5th occurrence of pipe '|' for clsPos
For k = 1 To 5
clsPos = InStr(clsPos + 1, sheet5.Range("D7"), "|", vbTextCompare)
Next k

'Displaying the value between openPos and clsPos
txtBetween = Mid(sheet5.Range("D7").Value, openPos + 1, clsPos - openPos - 1)
MsgBox ("Current Header 1 value: " & txtBetween)

enter image description here