Question

由于“＆amp;”，我的NSXMLParsing无效我的代码在下面。请帮忙吗？

 NSString *myRequestString = [NSString stringWithFormat:@"http://abc.com/def/webservices/aa.php?family_id=%d",self.passFamilyId];
//NSLog(@"Requested Service = %@",myRequestString);
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:myRequestString]];
[request setHTTPMethod: @"POST" ];
NSData *downloadedData = [ NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

NSString *str = [[NSString alloc] initWithData:downloadedData encoding:NSASCIIStringEncoding];
//NSString *contentString = [str stringByReplacingOccurrencesOfString:@"&" withString:@"&amp;"];
NSData * data=[str dataUsingEncoding:NSUTF8StringEncoding];


//NSLog (@"string is :%@" ,str);    

NSXMLParser *xmlParser = [[NSXMLParser alloc] initWithData:data];   

// Call the XMLParsers's initXMLParse method.
ClientDetailXmlParser *parser = (ClientDetailXmlParser*)[[ClientDetailXmlParser alloc] initXMLParser];
[xmlParser setDelegate:parser];
BOOL success = [xmlParser parse];

// Check for XML parsing.
if(success) 
{
    NSLog(@"No Errors in clientDetailXml.xml");     
}
else 
{
    NSLog(@"Error Error Error in clientDetailXml.xml!!!");
}   

[parser release];
parser = nil;

if (objClientAddUpdate != nil) {
    [objClientAddUpdate createBubbleList];
}

Answer 1

替换

NSString *str = [[NSString alloc] initWithData:downloadedData encoding:NSASCIIStringEncoding];
//NSString *contentString = [str stringByReplacingOccurrencesOfString:@"&" withString:@"&amp;"];
NSData * data=[str dataUsingEncoding:NSUTF8StringEncoding];

使用：

NSString *str = [[NSString alloc] initWithData:downloadedData encoding:NSASCIIStringEncoding];
NSString *contentString = [str stringByReplacingOccurrencesOfString:@"&" withString:@"&amp;"];
NSData * data=[contentString dataUsingEncoding:NSUTF8StringEncoding];

Answer 2

这对我有用：

NSString *response = [[NSString alloc]initWithData:dataResponse encoding:NSUTF8StringEncoding];
NSString *newResponse = [response stringByReplacingOccurrencesOfString:@"&amp:" withString:@"AND"];
NSData *dataObj = [newResponse dataUsingEncoding:NSUTF8StringEncoding];

如果我用符号＆＃39;＆amp;＆＃39;替换它，响应将是正确的，但它会抛出解析错误：68。所以我不得不使用＆＃39;和＆＃39;。< / p>

Answer 3

与sepehr-mahmoudian的答案非常相似，但是除了替换任何＆之外，您还应该只替换未转义的＆字符，为此，您可以使用正则表达式：

NSString *str = [[NSString alloc] initWithData:downloadedData encoding:NSASCIIStringEncoding];
//NSString *contentString = [str stringByReplacingOccurrencesOfString:@"&" withString:@"&amp;"];
NSData * data=[str dataUsingEncoding:NSUTF8StringEncoding];

使用：

NSString *str = [[NSString alloc] initWithData:downloadedData encoding:NSASCIIStringEncoding];

NSRange searchedRange = NSMakeRange(0, [str length]);
NSString *pattern = @"&(?!(#[0-9]{2,4}|[A-z]{2,6});)";
NSError *error = nil;

NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&error];
str = [regex stringByReplacingMatchesInString:str options:0 range:searchedRange withTemplate:@"&amp;"];

NSData *data = [str dataUsingEncoding:NSUTF8StringEncoding];

NSXMLParser问题与“＆amp;”（＆符号）字符有关

3 个答案: