Question

我有一个名为Call_Data的表，数据如下：

Arr_Date                   Interval    Han_Time   SL_Time  
2011-03-16 18:39:31.000    1830        1200       245
2011-03-16 20:06:03.000    2000        261        85
2011-03-31 00:35:42.000    0030        1900       400
2011-03-31 02:13:06.000    0200        2000       350

现在我想知道Han_time＆gt;的记录数量。 1800和SL_Time> 300

所以我写了两个查询来做到这一点：

  Select Arr_Date, Interval,
    Count(*) AS Han_Time_1800
    From Call_Data
    where Han_Time>1800
    Group by Arr_Date,Interval
    Order by Arr_Date,Interval

Select Arr_Date, Interval,
Count(*) AS SL_Time_300
From Call_Data
where SL_Time>300
Group by Arr_Date,Interval
Order by Arr_Date,Interval

有没有办法可以在一个查询中同时获取这两个值？

Answer 1

select Arr_Date,
       Interval,
       sum(case when Han_Time > 1800 then 1 else 0 end) as Han_Time_1800,
       sum(case when SL_Time > 300 then 1 else 0 end) as SL_Time_300
from Call_Data
where Han_Time > 1800 or 
      SL_Time > 300
group by Arr_Date, Interval
order by Arr_Date, Interval

Answer 2

这会有所帮助：

Select Arr_Date, Interval,
    Count(*) AS Han_Time_1800
    From Call_Data
    where Han_Time>1800
    and SL_Time>300
    Group by Arr_Date,Interval
    Order by Arr_Date,Interval

结合两个时间间隔查询

2 个答案: