Question

我有一个简单的restful服务，它使用RestEasy将JAXB-anntotated bean转换为响应XML。 XML标记可以包含转义的特殊字符（例如＆amp;＃8211;）。但RestEasy marshaller再一次逃脱了＆符号，我得到了＆amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp; amp;而不是＆amp;＃8211;在结果XML中。

我应该如何避免不必要的＆符号逃脱？

Answer 1

我一直在寻找它，我无法找到微调RESTEasy在写出响应时逃脱字符的方式。我正在使用拦截器来阻止这种编码。

作为参考，它在编码UTF-8 XML时在堆栈中的setEscape（）发生。

Encoded.setEscape(String, boolean) line: 107    
UTF8XmlOutput.doText(String, boolean) line: 315 
UTF8XmlOutput.text(String, boolean) line: 299   
XMLSerializer.leafElement(Name, String, String) line: 325   
RuntimeBuiltinLeafInfoImpl$1.writeLeafElement(XMLSerializer, Name, String, String) line: 210    
RuntimeBuiltinLeafInfoImpl$1.writeLeafElement(XMLSerializer, Name, Object, String) line: 209    
TransducedAccessor$CompositeTransducedAccessorImpl<BeanT,ValueT>.writeLeafElement(XMLSerializer, Name, BeanT, String) line: 250 
SingleElementLeafProperty<BeanT>.serializeBody(BeanT, XMLSerializer, Object) line: 98   
ClassBeanInfoImpl<BeanT>.serializeBody(BeanT, XMLSerializer) line: 332  
XMLSerializer.childAsXsiType(Object, String, JaxBeanInfo, boolean) line: 699    
SingleElementNodeProperty<BeanT,ValueT>.serializeBody(BeanT, XMLSerializer, Object) line: 152   
ClassBeanInfoImpl<BeanT>.serializeBody(BeanT, XMLSerializer) line: 332  
XMLSerializer.childAsSoleContent(Object, String) line: 593  
ClassBeanInfoImpl<BeanT>.serializeRoot(BeanT, XMLSerializer) line: 320  
XMLSerializer.childAsRoot(Object) line: 494 
MarshallerImpl.write(Object, XmlOutput, Runnable) line: 315 
MarshallerImpl.marshal(Object, Result) line: 244    
MarshallerImpl(AbstractMarshallerImpl).marshal(Object, OutputStream) line: 75   
JAXBXmlRootElementProvider(AbstractJAXBProvider<T>).writeTo(T, Class<?>, Type, Annotation[], 
...

在RestEasy XML响应中禁用anpersand转义

1 个答案: