java.net.ConnectException:/192.168.1.106:8002 - 拒绝连接(Android异常)

时间:2011-09-01 10:28:56

标签: java android sockets socketexception

我现在正面临这个问题。

我能够向设备发送命令并从设备接收到从android模拟器到套接字的响应。

但是,当我在平板电脑上安装相同的应用程序时,会出现问题。我第一次发送命令来检查设备是否已连接状态,它会向我发送设备已连接的响应,但是当我第二次发送命令时,它会抛出以下异常:

  

java.net.ConnectException:/192.168.1.106:8002 - 拒绝连接。

这是执行请求的代码:

public static String sendRequestandResponse(final String host,final int  port,
            final String command,
            final int timeoutInMillis,final int responseLength) throws UnknownHostException,NetworkSettingException

            {
        if (host == null)
        {
            throw new NullPointerException("host is null");  //NOPMD
        }
        Socket clientSocket=null;
        try {

            /**
             * Creating socket connection with IP address and port number to send Command
             */
            try{
                clientSocket = new Socket();

                SocketAddress remoteAdr = new InetSocketAddress(host, port);
                clientSocket.connect(remoteAdr, 1000);
                clientSocket.setSoTimeout(timeoutInMillis);
            }catch (Exception e) {
                e.printStackTrace();
                throw new NetworkSettingException(e.getMessage());
            }




            final PrintWriter outPutStream = new PrintWriter(new OutputStreamWriter(clientSocket.getOutputStream(), CHARSET));
            try
            {
                outPutStream.print(command);
                        outPutStream.flush();
                    BufferedReader responseString = new BufferedReader(new InputStreamReader(clientSocket.getInputStream(), CHARSET));
                response   = new StringBuilder(); 
                try
                {

                    int pos = 0;
                    while (true)
                    {
                        pos++;
                        System.out.println(pos);
                        int i=responseString.read();
                        byte[] resp={(byte)i};
                        System.out.println(new String(resp));
                        response.append(new String(resp));
                        if(pos>=responseLength){
                            {
                                clientSocket.shutdownInput();
                                clientSocket.shutdownOutput();
                                clientSocket.close();
                                Log.d("ConnectionSocket", "Socket closed with break");
                                break;
                            }


                        }
                    }

                }catch (Exception e) {
                    e.printStackTrace();
                }
                finally
                {
                    responseString.close();
                }


            }
            finally
            {
                outPutStream.close();
            }

        }

        catch(IOException ex){
        }
        catch(NullPointerException ex){  //NOPMD
        }

        finally
        {
            try {
                clientSocket.shutdownInput();
                clientSocket.shutdownOutput();
                clientSocket.close();
            } catch (NullPointerException ex) { //NOPMD
            } catch (IOException ex) {
            }
        }
        return response.toString();
            }

我认为它第一次没有关闭套接字,所以第二次拒绝连接。

相同的代码可以在模拟器上运行。

1 个答案:

答案 0 :(得分:0)

只有在服务器不接受连接时才会拒绝连接。

大多数情况下,问题是阻止任何不受信任的传入连接的防火墙。

我的应用程序主要在服务器有阻止它的防火墙时显示此消息。

因此,您可以在防火墙中为您的应用程序添加例外列表。