Question

我们使用JPA和hibernate作为提供者，我们有一个查询，其中包含FROM子句中带子查询的连接，但是我们收到以下错误：

org.hibernate.hql.ast.QuerySyntaxException：意外令牌:(近第1行，第75列[SELECT sd FROM com.hp.amber.datamodel.entities.analysis.SnapshotDates sd，（SELECT max（x.changeDate）maxChangeDate，x.viewId，x.state FROM com.hp.amber.datamodel.entities.analysis.SnapshotDates x WHERE x.changeDate＆lt;：date和x.viewId in（：viewIds）AND x.state =：state GROUP BY x.viewId，x.state）sd2 WHERE sd.viewId = sd2.viewId AND sd.state = ：state AND sd.changeDate = sd2.maxChangeDate]

这是查询：

SELECT sd 
FROM SnapshotDates sd, 
     (SELECT max(x.changeDate) maxChangeDate, x.viewId, x.state 
      FROM SnapshotDates x
     WHERE x.changeDate<:date AND x.viewId in (:viewIds) AND x.state=:state
GROUP BY x.viewId, x.state) sd2
WHERE sd.viewId = sd2.viewId 
      AND sd.state = :state 
      AND sd.changeDate = sd2.maxChangeDate

感谢您的帮助

Answer 1

我不认为HQL可以在from子句

中执行子查询

https://docs.jboss.org/hibernate/orm/4.3/manual/en-US/html/ch16.html#queryhql-subqueries

注意句子：

请注意，HQL子查询只能出现在select或where子句中。

我想你可以将它改成原生查询并以这种方式执行。

Answer 2

你的SQL是：

SELECT sd FROM SnapshotDates sd，（SELECT max（x.changeDate）maxChangeDate，x.viewId，x.state 从SnapshotDates x WHERE x.changeDate＆lt;：date和x.viewId in（：viewIds）AND x.state =：state GROUP BY x.viewId，x.state）sd2 WHERE sd.viewId = sd2.viewId AND sd.state =：state AND sd.changeDate = sd2.maxChangeDate

您可以重写您的sql，如

SELECT sd 
FROM SnapshotDates sd, 
WHERE sd.viewId in (:viewIds)
    AND sd.state = :state
    sd.changeDate = (SELECT max(x.changeDate) FROM SnapshotDates x WHERE x.viewId = ds.viewId AND x.state = ds.state)

从示例中获取灵感

SELECT m FROM Professor m WHERE (SELECT COUNT(e) FROM Professor e WHERE e.manager = m) > 0

http://www.java2s.com/Code/Java/JPA/EJBQLWhereClauseWithSubQuery.htm

我的类似例子我有SQL

select k.* from kredits k, 
  (select client_id, max(r_date) r_date from kredits k group by client_id) k2 
where k.client_id = k2.client_id 
    AND k.r_date = k2.r_date 
order by k.id

为PQL重写它

select k From Kredit k
where k.rDate = (select MAX(k2.rDate) from Kredit k2 where k2.clientId = k.clientId)
order by k.id

它将被翻译为

select kredit0_.id as id28_, kredit0_.client_id as client59_28_ from kredits kredit0_ 
where kredit0_.r_date=(select MAX(kredit1_.r_date) from kredits kredit1_ where kredit1_.client_id=kredit0_.client_id) 
order by kredit0_.id

返回与SQL相同的结果。

将Hebirnate 3.3.1与MySQL 5.0.24一起使用

from子句中的JPA / hibernate子查询

2 个答案: