我的问题是,如何解决以下问题:
如果我点击JTable中的一个单元格,我想改变它的背景。如果我释放鼠标按钮,我希望背景更改回正常颜色。
这可能吗?
问候ayk
答案 0 :(得分:5)
要在视觉领域进行,你需要
听众的一些代码
MouseListener l = new MouseAdapter() {
/**
* @inherited <p>
*/
@Override
public void mousePressed(MouseEvent e) {
JTable table = (JTable) e.getComponent();
int col = table.columnAtPoint(e.getPoint());
int row = table.rowAtPoint(e.getPoint());
if (col < 0 || row < 0) {
table.putClientProperty("pressedCell", null);
} else {
table.putClientProperty("pressedCell", new Point(col, row));
}
}
/**
* @inherited <p>
*/
@Override
public void mouseReleased(MouseEvent e) {
((JTable) e.getComponent()).putClientProperty("pressedCell", null);
}
};
table.addMouseListener(l);
PropertyChangeListener property = new PropertyChangeListener() {
@Override
public void propertyChange(PropertyChangeEvent evt) {
JTable table = (JTable) evt.getSource();
Point cell = evt.getNewValue() != null ?
(Point) evt.getNewValue() : (Point) evt.getOldValue();
if (cell != null) table.repaint(table.getCellRect(cell.y, cell.x, false));
}
};
table.addPropertyChangeListener("pressedCell", property);
在SwingX中突出显示单元格(无法抵抗:-)
HighlightPredicate predicate = new HighlightPredicate() {
@Override
public boolean isHighlighted(Component renderer, ComponentAdapter adapter) {
Point p = (Point) adapter.getComponent().getClientProperty("pressedCell");
return p != null && p.x == adapter.column && p.y == adapter.row;
}
};
table.addHighlighter(new ColorHighlighter(predicate, Color.YELLOW, null, Color.YELLOW, null));
对于核心Swing,要么实现自定义TableCellRenderer,要么子类化JTable并覆盖prepareRenderer以根据单元格标志设置背景颜色,如Rob的Table Row Rendering
中所述。答案 1 :(得分:4)
,您必须覆盖hasFocus
例如
import java.awt.*;
import java.util.*;
import javax.swing.*;
import javax.swing.table.*;
public class TableRenderer extends JFrame {
private static final long serialVersionUID = 1L;
private JTable table;
private String[] columnNames = {"Date", "String", "Centered", "Integer", "Boolean"};
private Object[][] data = {
{new Date(), "A", "A", new Integer(1), true},
{new Date(), "B", "B", new Integer(2), false},
{new Date(), "C", "C", new Integer(10), null},
{new Date(), "D", "D", new Integer(4), false}
};
public TableRenderer() {
DefaultTableModel model = new DefaultTableModel(data, columnNames);
table = new JTable(model) {
private static final long serialVersionUID = 1L;
// Returning the Class of each column will allow different
// renderers to be used based on Class
@Override
public Class getColumnClass(int column) {
return getValueAt(0, column).getClass();
}
};
table.setPreferredScrollableViewportSize(table.getPreferredSize());
JScrollPane scrollPane = new JScrollPane(table);
getContentPane().add(scrollPane);
// Override default renderer on a specific Class
TableCellRenderer colorRenderer = new ColorRenderer();
table.setDefaultRenderer(String.class, colorRenderer);
// Override default renderer for a specific column
DefaultTableCellRenderer centerRenderer = new DefaultTableCellRenderer();
centerRenderer.setHorizontalAlignment(JLabel.CENTER);
table.getColumnModel().getColumn(2).setCellRenderer(centerRenderer);
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
TableRenderer frame = new TableRenderer();
frame.setDefaultCloseOperation(EXIT_ON_CLOSE);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
/*
** Color the focused cell
*/
private class ColorRenderer extends DefaultTableCellRenderer {
private static final long serialVersionUID = 1L;
@Override
public Component getTableCellRendererComponent(
JTable table, Object value, boolean isSelected, boolean hasFocus, int row, int column) {
super.getTableCellRendererComponent(table, value, isSelected, hasFocus, row, column);
if (hasFocus) {
setBackground(Color.cyan);
} else if (isSelected) {
setBackground(table.getSelectionBackground());
} else {
setBackground(table.getBackground());
}
return this;
}
}
}
答案 2 :(得分:1)
是的,这是可能的。 使用自定义ListSelectionModel并将您的JTable设置为使用:setSelectionModel()。
这是一个example。