我正在尝试使用jquery将复杂的数据结构发布到我的服务器端方法。
public partial class SerializeJSON : System.Web.UI.Page
{
[System.Web.Services.WebMethod]
public static string GetData(List<Customer> oCust)
{
int empid = oCust[0].EmpID;
string name = oCust[0].Name.ToString();
DateTime dob = oCust[0].BirthDate;
double sal = oCust[0].Salary;
Address add = oCust[0].Address[0];
return "";
}
}
public class Customer
{
List<Address> add = null;
public Customer()
{
add = new List<Address>();
}
public int EmpID { get; set; }
public string Name { get; set; }
public DateTime BirthDate { get; set; }
public List<Address> Address
{
get { return add; }
set { add = value; }
}
public double Salary { get; set; }
}
public class Address
{
public string Address1 { get; set; }
public string Address2 { get; set; }
public string PostCode { get; set; }
}
我知道json的样子是什么样的。正确的json将是
[
{
"EmpID":1,
"Name":"Keith",
"BirthDate":"\/Date(947874600000)\/",
"Address":[{"Address1":"Salt lake","Address2":"Kolkata","PostCode":"784512"}],"Salary":5200
}
这里我告诉你如何将数据实际从我的客户端发送到服务器端 这是我的javascript代码，我在客户端填充数据，最近我发送这个像
var Person = {};
Person["EmpID"] = 1;
Person["Name"] = "Keith";
Person["BirthDate"] = "08/15/2011";
var Address = {};
Address["Address1"] = "Salt lake";
Address["Address2"] = "Kolkata";
Address["PostCode"] = "741258";
Person["Address"] = Address;
$(function () {
$('#btnSubmit').click(function () {
alert(JSON.stringify(Person));
$.ajax({
type: "POST",
url: "SerializeJSON.aspx/GetData",
data: "{'oCust':'" + JSON.stringify(Person) + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (data) {
}
,
error: function (XMLHttpRequest, textStatus, errorThrown) {
alert(textStatus);
}
});
return false;
});
});
但我收到了错误。 JSON.stringify（）没有生成正确的json。 所以请告诉我填充和放置的最佳方法是什么？以编程方式生成正确的json数据。有一件事我需要说，我不想手动生成json，而是告诉我以编程方式生成正确的json。
所以指导我如何使用javascript以编程方式生成正确的json。
也告诉我使用javascript填充数据的方法是错误的。
var Person = {};
Person["EmpID"] = 1;
Person["Name"] = "Keith";
Person["BirthDate"] = "08/15/2011";
var Address = {};
Address["Address1"] = "Salt lake";
Address["Address2"] = "Kolkata";
Address["PostCode"] = "741258";
Person["Address"] = Address;
上面的代码是错误的方法。
所以请指导我如何使用javascript生成正确的json，可以在服务器端轻松反序列化。感谢
var Persons = [];
var Person = {}; 人[“EmpID”] = 1; 人[“姓名”] =“基思”; 人[“BirthDate”] =“08/15/2011”;
var Address = []; var addr = {}; addr [“Address1”] =“盐湖”; addr [“Address2”] =“加尔各答”; addr [“PostCode”] =“741258”; Address.push（ADDR）;
Person["Address"] = Address;
Persons.push(Person)
var DTO = {oCust：Persons} data：JSON.stringify（DTO）
我希望它现在能够发挥作用......不是吗？
var Persons = [];
var Person = {}; 人[“EmpID”] = 1; 人[“姓名”] =“基思”; 人[“BirthDate”] =“08/15/2011”;
var Address = []; var addr = {}; addr [“Address1”] =“盐湖”; addr [“Address2”] =“加尔各答”; addr [“PostCode”] =“741258”; Address.push（ADDR）;
Person["Address"] = Address;
var DTO = {oCust：Person} data：JSON.stringify（DTO）
我是对的吗？public partial class SerializeJSON：System.Web.UI.Page {
[System.Web.Services.WebMethod]
public static string GetData(Customer oCust)
{
int empid = oCust.EmpID;
string name = oCust.Name.ToString();
DateTime dob = oCust.BirthDate;
double sal = oCust.Salary;
Address add = oCust.Address[0];
return "";
}
}
public class Customer
{
List<Address> add = null;
public Customer()
{
add = new List<Address>();
}
public int EmpID { get; set; }
public string Name { get; set; }
public DateTime BirthDate { get; set; }
public List<Address> Address
{
get { return add; }
set { add = value; }
}
public double Salary { get; set; }
}
public class Address
{
public string Address1 { get; set; }
public string Address2 { get; set; }
public string PostCode { get; set; }
}
答案 0 :(得分：5)
这是使用WebMethod自动反序列化复杂JSON的片段 如果有疑问，请仔细阅读评论。
类
public class Customer
{
public int EmpID { get; set; }
public string Name { get; set; }
public DateTime BirthDate { get; set; }
// why did you use the conventional get set in this case?
// feel free to revert if you are using the class elsewhere.
public List<Address> Address { get; set; }
public double Salary { get; set; }
}
public class Address
{
public string Address1 { get; set; }
public string Address2 { get; set; }
public string PostCode { get; set; }
}
的WebMethod
[System.Web.Services.WebMethod]
public static string GetData(Customer oCust)
{
try
{
int empid = oCust.EmpID;
string name = oCust.Name.ToString();
DateTime dob = oCust.BirthDate;
double sal = oCust.Salary;
Address add = oCust.Address[0];
return "Success";
}
catch (Exception exception)
{
//Elmah.ErrorSignal.FromCurrentContext().Raise(exception);
return "Failed";
}
}
AJAX致电
$(function () {
$('#btnSubmit').click(function (evt) {
var Person = {};
Person["EmpID"] = 1;
Person["Name"] = "Keith";
//converting to date is not mandatory, but its more typesafe
Person["BirthDate"] = new Date("08/15/2011");
var Address = [];
var addr = {};
addr["Address1"] = "Salt lake";
addr["Address2"] = "Kolkata";
addr["PostCode"] = "741258";
Address.push(addr);
Person["Address"] = Address;
var DTO = { oCust: Person }
//save yourself some typing. dataType and charset in content type are not needed.
//Courtesy: http://encosia.com/save-yourself-some-typing-when-you-call-asp-net-services/
$.ajax({
type: "POST",
url: "SerializeJSON.aspx/GetData",
data: JSON.stringify(DTO),
contentType: "application/json",
success: function (msg) {
//ASP.NET 2.0 fallback.
var data = msg.hasOwnProperty("d") ? msg.d : msg;
//place a div with id=content to show the result.(not mandatory)
$("#content").hide().html(msg.d).delay(1000).show(400);
},
error: function (xhr, textStatus, errorThrown) {
//you should ideally call the xhr.responseText to see the error
alert(xhr.responseText);
}
});
evt.preventDefault();
});
});
HTML
<div id="content"></div>
<asp:Button ID="btnSubmit" runat="server" Text="Submit"/>
希望这有帮助。