Question

我有这个PHP：

$handle = fopen($_FILES["csvfile"]["tmp_name"], "r");

while (($data = fgetcsv($handle, 5000, ",", '"')) !== FALSE) {
    echo "<pre>";
    print_r($data);
    echo "<pre>";
}

<form method="post">
<input type="file" name="csvfile">
<input type="submit>

CSV由html <input type="file">提供。现在它打印出的数组只是第一个值和逗号或每一行，而不是打印出每行11个值的数组。我做到了做正确的事情，但不知何故搞砸了我的代码，无法弄清楚我做了什么。

以下是CSV的示例：

"lorem","ipsum","dolor","sit","amet","consectetuer","adipiscing","elit","sed ","diam","nonummy",

Answer 1

在您发布的相同代码上，我得到了一个很好的格式化结果

file_put_contents( 'tmp.tmp',
'"lorem","ipsum","dolor","sit","amet","consectetuer","adipiscing","elit","sed ","diam","nonummy",
"1lorem","1ipsum","1dolor","1sit","amet","consectetuer","adipiscing","elit","sed ","diam","nonummy",
');

$handle = fopen("tmp.tmp", "r");

while (($data = fgetcsv($handle, 5000, ",", '"')) !== FALSE) {
    echo "<pre>";
    print_r($data);
    echo "<pre>";
}

我明白了：

阵（ [0] =＆gt; LOREM [1] =＆gt;存有 [2] =＆gt;悲 [3] =＆gt;坐 [4] =＆gt;阿梅德 [5] =＆gt; consectetuer [6] =＆gt; adipiscing [7] =＆gt; ELIT [8] =＆gt; SED [9] =＆gt;直径 [10] =＆gt; nonummy [11] =＆gt; ）

你可能在其他地方做错了，而没有注意到它。

为什么这个PHP fgetcsv（）只显示csv的某些部分？

1 个答案: