我的代码是
ContentValues values;
values = new ContentValues();
values.put(SQLHelper.EMPLOYEE_LPN, jsObj.getString("lpn"));
db.update(SQLHelper.EMPLOYEE_TABLE, values,
"EMPLOYEE_LPN ='" + jsObj.getString("lpn") + "'",
null);
Log Cat中显示警告
08-31 15:19:45.297: WARN/Database(2868): Reached MAX size for compiled-sql statement cache for database /data/data/org.sipdroid.sipua/databases/test.db; i.e.,
NO space for this sql statement in cache:
SELECT EMPLOYEE_NAME FROM eyemployee WHERE EMPLOYEE_LPN ='1169162'.
Please change your sql statements to use '?' for bindargs, instead of using actual values
如何解决?
答案 0 :(得分:12)
查看示例8-3和8-4 here。
例8-3。使用更新方法
/**
* Update a job in the database.
* @param job_id The job id of the existing job
* @param employer_id The employer offering the job
* @param title The job title
* @param description The job description
*/
public void editJob(long job_id, long employer_id, String title, String description) {
ContentValues map = new ContentValues();
map.put("employer_id", employer_id);
map.put("title", title);
map.put("description", description);
String[] whereArgs = new String[]{Long.toString(job_id)};
try{
getWritableDatabase().update("jobs", map, "_id=?", whereArgs);
} catch (SQLException e) {
Log.e("Error writing new job", e.toString());
}
}
以下是示例8-3中代码的一些要点:
示例8-4显示了如何使用execSQL方法 例8-4。使用execSQL方法
/**
* Update a job in the database.
* @param job_id The job id of the existing job
* @param employer_id The employer offering the job
* @param title The job title
* @param description The job description
*/
public void editJob(long job_id, long employer_id, String title, String description) {
String sql =
"UPDATE jobs " +
"SET employer_id = ?, "+
" title = ?, "+
" description = ? "+
"WHERE _id = ? ";
Object[] bindArgs = new Object[]{employer_id, title, description, job_id};
try{
getWritableDatabase().execSQL(sql, bindArgs);
} catch (SQLException e) {
Log.e("Error writing new job", e.toString());
}
}
该消息要求您使参数使用sql变量而不是sql literals。
解析每个sql查询,生成计划并存储在sql语句缓存中。
从缓存中提取具有相同文本的查询。
--One query
SELECT * FROM Customers WHERE Id = @1 (@1 = 3)
SELECT * FROM Customers WHERE Id = @1 (@1 = 4)
SELECT * FROM Customers WHERE Id = @1 (@1 = 5)
在缓存中找不到具有不同文本(包括文字)的查询,并且(无用地)添加了查询。
--Three Queries.
SELECT * FROM Customers WHERE Id = 3
SELECT * FROM Customers WHERE Id = 4
SELECT * FROM Customers WHERE Id = 5
答案 1 :(得分:2)
我今天正在寻找这个,并且遇到了这个文档。
http://ormlite.com/docs/query-builder
这解决了我的问题。这是上面链接中的代码
QueryBuilder<Account, String> queryBuilder =
accountDao.queryBuilder();
Where<Account, String> where = queryBuilder.where();
SelectArg selectArg = new SelectArg();
// define our query as 'name = ?'
where.eq(Account.NAME_FIELD_NAME, selectArg);
// prepare it so it is ready for later query or iterator calls
PreparedQuery<Account> preparedQuery = queryBuilder.prepare();
// later we can set the select argument and issue the query
selectArg.setValue("foo");
List<Account> accounts = accountDao.query(preparedQuery);
// then we can set the select argument to another
// value and re-run the query
selectArg.setValue("bar");
accounts = accountDao.query(preparedQuery);