我想列出UIViewController
中的所有子视图。我尝试了self.view.subviews
,但并未列出所有子视图,例如,找不到UITableViewCell
中的子视图。有什么想法吗?
答案 0 :(得分:169)
您必须递归迭代子视图。
- (void)listSubviewsOfView:(UIView *)view {
// Get the subviews of the view
NSArray *subviews = [view subviews];
// Return if there are no subviews
if ([subviews count] == 0) return; // COUNT CHECK LINE
for (UIView *subview in subviews) {
// Do what you want to do with the subview
NSLog(@"%@", subview);
// List the subviews of subview
[self listSubviewsOfView:subview];
}
}
正如@Greg Meletic评论的那样,你可以跳过上面的COUNT CHECK LINE。
答案 1 :(得分:35)
转储视图层次结构的xcode / gdb内置方法很有用 - recursiveDescription,per http://developer.apple.com/library/ios/#technotes/tn2239/_index.html
它会输出一个更完整的视图层次结构,您可能会发现它很有用:
> po [_myToolbar recursiveDescription]
<UIToolbarButton: 0xd866040; frame = (152 0; 15 44); opaque = NO; layer = <CALayer: 0xd864230>>
| <UISwappableImageView: 0xd8660f0; frame = (0 0; 0 0); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0xd86a160>>
答案 2 :(得分:13)
您需要递归打印,此方法还会根据视图的深度选项卡
-(void) printAllChildrenOfView:(UIView*) node depth:(int) d
{
//Tabs are just for formatting
NSString *tabs = @"";
for (int i = 0; i < d; i++)
{
tabs = [tabs stringByAppendingFormat:@"\t"];
}
NSLog(@"%@%@", tabs, node);
d++; //Increment the depth
for (UIView *child in node.subviews)
{
[self printAllChildrenOfView:child depth:d];
}
}
答案 3 :(得分:12)
Swift中优雅的递归解决方案:
extension UIView {
func subviewsRecursive() -> [UIView] {
return subviews + subviews.flatMap { $0.subviewsRecursive() }
}
}
你可以在任何UIView上调用subviewsRecursive():
let allSubviews = self.view.subviewsRecursive()
答案 4 :(得分:11)
这是swift版本
func listSubviewsOfView(view:UIView){
// Get the subviews of the view
var subviews = view.subviews
// Return if there are no subviews
if subviews.count == 0 {
return
}
for subview : AnyObject in subviews{
// Do what you want to do with the subview
println(subview)
// List the subviews of subview
listSubviewsOfView(subview as UIView)
}
}
答案 5 :(得分:7)
我参加聚会有点晚了,但是更通用的解决方案:
@implementation UIView (childViews)
- (NSArray*) allSubviews {
__block NSArray* allSubviews = [NSArray arrayWithObject:self];
[self.subviews enumerateObjectsUsingBlock:^( UIView* view, NSUInteger idx, BOOL*stop) {
allSubviews = [allSubviews arrayByAddingObjectsFromArray:[view allSubviews]];
}];
return allSubviews;
}
@end
答案 6 :(得分:5)
如果你想要的只是一个UIView
的数组,这是一个单线解决方案( Swift 4 + ):
extension UIView {
var allSubviews: [UIView] {
return self.subviews.reduce([UIView]()) { $0 + [$1] + $1.allSubviews }
}
}
答案 7 :(得分:5)
我用这种方式:
NSLog(@"%@", [self.view subviews]);
在UIViewController中。
答案 8 :(得分:4)
extension UIView {
private func subviews(parentView: UIView, level: Int = 0, printSubviews: Bool = false) -> [UIView] {
var result = [UIView]()
if level == 0 && printSubviews {
result.append(parentView)
print("\(parentView.viewInfo)")
}
for subview in parentView.subviews {
if printSubviews { print("\(String(repeating: "-", count: level))\(subview.viewInfo)") }
result.append(subview)
if subview.subviews.isEmpty { continue }
result += subviews(parentView: subview, level: level+1, printSubviews: printSubviews)
}
return result
}
private var viewInfo: String { return "\(classForCoder), frame: \(frame))" }
var allSubviews: [UIView] { return subviews(parentView: self) }
func printSubviews() { _ = subviews(parentView: self, printSubviews: true) }
}
view.printSubviews()
print("\(view.allSubviews.count)")
答案 9 :(得分:3)
以我的方式,UIView的类别或扩展比其他人好得多 和递归是获取所有子视图的关键点
了解更多:
https://github.com/ZhipingYang/XYDebugView
@implementation UIView (Recurrence)
- (NSArray<UIView *> *)recurrenceAllSubviews
{
NSMutableArray <UIView *> *all = @[].mutableCopy;
void (^getSubViewsBlock)(UIView *current) = ^(UIView *current){
[all addObject:current];
for (UIView *sub in current.subviews) {
[all addObjectsFromArray:[sub recurrenceAllSubviews]];
}
};
getSubViewsBlock(self);
return [NSArray arrayWithArray:all];
}
@end
示例强>
NSArray *views = [viewController.view recurrenceAllSubviews];
extension UIView {
func recurrenceAllSubviews() -> [UIView] {
var all = [UIView]()
func getSubview(view: UIView) {
all.append(view)
guard view.subviews.count>0 else { return }
view.subviews.forEach{ getSubview(view: $0) }
}
getSubview(view: self)
return all
}
}
示例强>
let views = viewController.view.recurrenceAllSubviews()
直接使用序列函数获取所有子视图
let viewSequence = sequence(state: [viewController.view]) { (state: inout [UIView] ) -> [UIView]? in
guard state.count > 0 else { return nil }
defer {
state = state.map{ $0.subviews }.flatMap{ $0 }
}
return state
}
let views = viewSequence.flatMap{ $0 }
答案 10 :(得分:2)
我写了一个类别来列出视图控制器持有的所有视图,其灵感来自之前发布的答案。
@interface UIView (ListSubviewHierarchy)
- (NSString *)listOfSubviews;
@end
@implementation UIView (ListSubviewHierarchy)
- (NSInteger)depth
{
NSInteger depth = 0;
if ([self superview]) {
deepth = [[self superview] depth] + 1;
}
return depth;
}
- (NSString *)listOfSubviews
{
NSString * indent = @"";
NSInteger depth = [self depth];
for (int counter = 0; counter < depth; counter ++) {
indent = [indent stringByAppendingString:@" "];
}
__block NSString * listOfSubviews = [NSString stringWithFormat:@"\n%@%@", indent, [self description];
if ([self.subviews count] > 0) {
[self.subviews enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
UIView * subview = obj;
listOfSubviews = [listOfSubviews stringByAppendingFormat:@"%@", [subview listOfSubviews]];
}];
}
return listOfSubviews;
}
@end
列出视图控制器持有的所有视图,仅NSLog("%@",[self listOfSubviews])
,self
表示视图控制器本身。虽然它没有退出效率。
另外,您可以使用NSLog(@"\n%@", [(id)self.view performSelector:@selector(recursiveDescription)]);
执行相同的操作,我认为它比我的实现更有效。
答案 11 :(得分:2)
Simple Swift示例:
var arrOfSub = self.view.subviews
print("Number of Subviews: \(arrOfSub.count)")
for item in arrOfSub {
print(item)
}
答案 12 :(得分:2)
未打印UITableViewCell中的子视图的原因是您必须输出顶级的所有子视图。单元格的子视图不是视图的直接子视图。
为了获取UITableViewCell的子视图,您需要确定哪些子视图属于您的打印循环中的UITableViewCell(使用isKindOfClass:
),然后遍历它的子视图
编辑:Easy UIView Debugging上的此博文可能有帮助
答案 13 :(得分:1)
兼容Swift 2.0
这是一个获取通用视图的所有子视图的递归方法:
extension UIView {
func subviewsList() -> [UIView] {
var subviews = self.subviews
if subviews.count == 0 {
return subviews + []
}
for v in subviews {
subviews += v.listSubviewsOfView()
}
return subviews
}
}
所以你可以用这种方式到处打电话:
let view = FooController.view
let subviews = view.subviewsList()
答案 14 :(得分:1)
最短的解决方案
for subview in self.view.subviews {
print(subview.dynamicType)
}
<强>结果强>
UIView
UIView
UISlider
UISwitch
UITextField
_UILayoutGuide
_UILayoutGuide
备注强>
答案 15 :(得分:1)
您可以尝试一种奇特的数组技巧,例如:
[self.view.subviews makeObjectsPerformSelector: @selector(printAllChildrenOfView)];
只需一行代码。当然,您可能需要调整方法printAllChildrenOfView
以不采用任何参数或制作新方法。
答案 16 :(得分:1)
重写this回复:
您必须首先获得要打印其所有子视图的对象的指针/引用。有时您可能会发现通过子视图访问它更容易找到该对象。像po someSubview.superview
一样。这会给你一些类似的东西:
Optional<UIView>
▿ some : <FacebookApp.WhatsNewView: 0x7f91747c71f0; frame = (30 50; 354 636); clipsToBounds = YES; layer = <CALayer: 0x6100002370e0>>
superview
0x7f91747c71f0
是指向superview的指针。要打印superView,必须使用断点。
现在要执行此步骤,您只需单击“查看调试层次结构”即可。无需断点
然后你可以很容易地做到:
po [0x7f91747c71f0 recursiveDescription]
对我来说,返回的内容如下:
<FacebookApp.WhatsNewView: 0x7f91747c71f0; frame = (30 50; 354 636); clipsToBounds = YES; layer = <CALayer: 0x6100002370e0>>
| <UIStackView: 0x7f91747c75f0; frame = (45 60; 264 93); layer = <CATransformLayer: 0x610000230ec0>>
| | <UIImageView: 0x7f916ef38c30; frame = (10.6667 0; 243 58); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x61000003b840>>
| | <UIStackView: 0x7f91747c8230; frame = (44.6667 58; 174.667 35); layer = <CATransformLayer: 0x6100006278c0>>
| | | <FacebookApp.CopyableUILabel: 0x7f91747a80b0; baseClass = UILabel; frame = (44 0; 86.6667 16); text = 'What's New'; gestureRecognizers = <NSArray: 0x610000c4a770>; layer = <_UILabelLayer: 0x610000085550>>
| | | <FacebookApp.CopyableUILabel: 0x7f916ef396a0; baseClass = UILabel; frame = (0 21; 174.667 14); text = 'Version 14.0.5c Oct 05, 2...'; gestureRecognizers = <NSArray: 0x610000c498a0>; layer = <_UILabelLayer: 0x610000087300>>
| <UITextView: 0x7f917015ce00; frame = (45 183; 264 403); text = ' • new Adding new feature...'; clipsToBounds = YES; gestureRecognizers = <NSArray: 0x6100000538f0>; layer = <CALayer: 0x61000042f000>; contentOffset: {0, 0}; contentSize: {264, 890}>
| | <<_UITextContainerView: 0x7f9170a13350; frame = (0 0; 264 890); layer = <_UITextTiledLayer: 0x6080002c0930>> minSize = {0, 0}, maxSize = {1.7976931348623157e+308, 1.7976931348623157e+308}, textContainer = <NSTextContainer: 0x610000117b20 size = (264.000000,340282346638528859811704183484516925440.000000); widthTracksTextView = YES; heightTracksTextView = NO>; exclusionPaths = 0x61000001bc30; lineBreakMode = 0>
| | | <_UITileLayer: 0x60800023f8a0> (layer)
| | | <_UITileLayer: 0x60800023f3c0> (layer)
| | | <_UITileLayer: 0x60800023f360> (layer)
| | | <_UITileLayer: 0x60800023eca0> (layer)
| | <UIImageView: 0x7f9170a7d370; frame = (-39 397.667; 36 2.33333); alpha = 0; opaque = NO; autoresize = TM; userInteractionEnabled = NO; layer = <CALayer: 0x60800023f4c0>>
| | <UIImageView: 0x7f9170a7d560; frame = (258.667 -39; 2.33333 36); alpha = 0; opaque = NO; autoresize = LM; userInteractionEnabled = NO; layer = <CALayer: 0x60800023f5e0>>
| <UIView: 0x7f916ef149c0; frame = (0 587; 354 0); layer = <CALayer: 0x6100006392a0>>
| <UIButton: 0x7f91747a8730; frame = (0 0; 0 0); clipsToBounds = YES; opaque = NO; layer = <CALayer: 0x610000639320>>
| | <UIButtonLabel: 0x7f916ef00a80; frame = (0 -5.66667; 0 16); text = 'See More Details'; opaque = NO; userInteractionEnabled = NO; layer = <_UILabelLayer: 0x610000084d80>>
因为你必须猜到我的超级视图有4个子视图:
这对我来说相当新,但帮助我调试了我的视图框架(以及文本和类型)。我的一个子视图没有显示在屏幕上,所以使用了recursiveDescription,我意识到我的一个subView的宽度是0
...所以我纠正了它的约束并且子视图出现了。
答案 17 :(得分:0)
- (NSString *)recusiveDescription:(UIView *)view
{
NSString *s = @"";
NSArray *subviews = [view subviews];
if ([subviews count] == 0) return @"no subviews";
for (UIView *subView in subviews) {
s = [NSString stringWithFormat:@"<%@; frame = (%f %f : %f %f) \n ",NSStringFromClass([subView class]), subView.frame.origin.x, subView.frame.origin.y ,subView.frame.size.width, subView.frame.size.height];
[self recusiveDescription:subView];
}
return s;
}
答案 18 :(得分:0)
或者,如果您想从UIView扩展中返回所有子视图(和嵌套子视图)的数组:
func getAllSubviewsRecursively() -> [AnyObject] {
var allSubviews: [AnyObject] = []
for subview in self.subviews {
if let subview = subview as? UIView {
allSubviews.append(subview)
allSubviews = allSubviews + subview.getAllSubviewsRecursively()
}
}
return allSubviews
}
答案 19 :(得分:0)
我在UIView
的类别中完成了它只是调用传递索引的函数以使用漂亮的树格式打印它们。这只是James Webster发布的答案的另一个选项。
#pragma mark - Views Tree
- (void)printSubviewsTreeWithIndex:(NSInteger)index
{
if (!self)
{
return;
}
NSString *tabSpace = @"";
@autoreleasepool
{
for (NSInteger x = 0; x < index; x++)
{
tabSpace = [tabSpace stringByAppendingString:@"\t"];
}
}
NSLog(@"%@%@", tabSpace, self);
if (!self.subviews)
{
return;
}
@autoreleasepool
{
for (UIView *subView in self.subviews)
{
[subView printViewsTreeWithIndex:index++];
}
}
}
我希望它有帮助:)
答案 20 :(得分:0)
C#Xamarin版本:
void ListSubviewsOfView(UIView view)
{
var subviews = view.Subviews;
if (subviews.Length == 0) return;
foreach (var subView in subviews)
{
Console.WriteLine("Subview of type {0}", subView.GetType());
ListSubviewsOfView(subView);
}
}
或者,如果您想查找我使用的特定类型的所有子视图:
List<T> FindViews<T>(UIView view)
{
List<T> allSubviews = new List<T>();
var subviews = view.Subviews.Where(x => x.GetType() == typeof(T)).ToList();
if (subviews.Count == 0) return allSubviews;
foreach (var subView in subviews)
{
allSubviews.AddRange(FindViews<T>(subView));
}
return allSubviews;
}
答案 21 :(得分:-1)
self.view.subviews维护着视图的层次结构。要获得uitableviewcell的子视图,你必须做类似下面的事情。
for (UIView *subView in self.view.subviews) {
if ([subView isKindOfClass:[UITableView class]]) {
for (UIView *tableSubview in subView.subviews) {
.......
}
}
}