如何在一个较长的字符串中使用Ruby以“H”开头的10个字符的子字符串进行匹配？

Question

我有以下字符串：

/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml

在Ruby中，如何提取以H开头的前10个字符子字符串，并在H之后包含9位数字（仅限数字）。在上面的示例中，子字符串将是H200000787

Answer 1

您需要

String#[]方法：

str = '/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml'

puts str[/H\d{9}/]     #=> H200000787

Answer 2

irb(main):001:0> s = "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
=> "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
irb(main):002:0> s =~ /H\d{9}/
=> 46
irb(main):003:0> $&
=> "H200000787"