弄清楚报警管理器

时间:2011-08-29 02:03:04

标签: android alarm

我正在尝试创建一个应用程序,在x分钟后将一些数据发送到网络服务器。我被告知警报管理器是最好的解决方案,只需在警报内额外拨打x分钟即可调用相同的警报功能,以便即使在后台也能不断发送数据。

但是我只看到了项目中的警报打开意图。这是否意味着它将在x分钟后切换到新意图,或者一切都在后台运行?

应该发送后台数据而不必在意图之间切换,所以我希望它只是在我的一个活动中调用一个函数。我应该怎么做呢?

这是我想每隔x分钟拨打一次的功能。

由于

public class updateloc extends AsyncTask<Void, Void, Void> {

    protected void onPostExecute(String response) {
        if (response != null) {
            // check if this does anything later
        }
        progressDialog.dismiss();
    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        progressDialog = ProgressDialog.show(ImTracking.this, "",
                "Updating Data...");
    }

    @Override
    protected Void doInBackground(Void... arg0) {
        SharedPreferences prefs = getSharedPreferences("Settings", 0);
        final String id = prefs.getString("ID", "");
        DefaultHttpClient httpclient = new DefaultHttpClient();
        HttpPost httpost = new HttpPost(
                "http://iphone-radar.com/gps/gps_locations");

        JSONObject holder = new JSONObject();

        try {
            holder.put("id", id);
            LocationManager locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
            Criteria criteria = new Criteria();
            criteria.setAccuracy(Criteria.ACCURACY_FINE);
            String bestProvider = locationManager.getBestProvider(criteria,
                    false);
            LocationListener loc_listener = new LocationListener() {

                @Override
                public void onStatusChanged(String provider, int status,
                        Bundle extras) {
                }
            };
            try {
                Looper.prepare();
                locationManager.requestLocationUpdates(bestProvider, 0, 0,
                        loc_listener);
            } catch (Exception e) {
                e.printStackTrace();
            }
            Location location = locationManager
                    .getLastKnownLocation(bestProvider);
            Calendar c = Calendar.getInstance();
            SimpleDateFormat sdf = new SimpleDateFormat(
                    "hh:mmaa MM/dd/yyyy");
            holder.put("time", sdf.format(c.getTime()));
            holder.put("time_since_epoch", System.currentTimeMillis());
            try {
                holder.put("lat", location.getLatitude());
                holder.put("lon", location.getLongitude());
            } catch (NullPointerException e) {
                try {
                    holder.put("lat", -1.0);
                    holder.put("lon", -1.0);
                } catch (JSONException e1) {
                    e1.printStackTrace();
                }
            }

            StringEntity se = new StringEntity(holder.toString());
            httpost.setEntity(se);
            httpost.setHeader("Accept", "application/json");
            httpost.setHeader("Content-type", "application/json");

            ResponseHandler responseHandler = new BasicResponseHandler();
            String response = httpclient.execute(httpost, responseHandler);
            org.json.JSONObject obj;

            obj = new org.json.JSONObject(response);

        } catch (JSONException e) {
            e.printStackTrace();
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        progressDialog.dismiss();
        return null;
    }
}

1 个答案:

答案 0 :(得分:1)

如果您希望在后台运行此功能,则需要创建服务。可以使用意图启动服务,因此您可以使用AlarmManager启动服务。看看IntentService,您只需要在servcie的AsyncTask方法中移动handleIntent()中当前正在执行的操作。