应用程序部署到越狱的iPhone后,奇怪的GDB行为

时间:2011-08-29 01:26:11

标签: iphone objective-c gdb nstask

我试图创建一个通过NSTask向GDB发送命令的应用程序,并将输出定向到UITextView。它适用于Mac(iOS模拟器)。但是,当部署到实际设备(iPhone)时,它不会在命令“info registers”之后显示任何寄存器。代码是这样的:

 - (void)viewDidLoad
{
self.title = @"GDB";

NSLog(@"Pid for GDB execution is :%@", pid);

UIBarButtonItem *btnClicked = [[UIBarButtonItem alloc] 
                               initWithTitle:@"Commands"                                            
                               style:UIBarButtonItemStyleBordered 
                               target:self 
                               action:@selector(btnClicked:)];
self.navigationItem.rightBarButtonItem = btnClicked;
[btnClicked release];


stringInput = @"info registers";



task = [[NSTask alloc] init];
[task setLaunchPath: @"/usr/bin/gdb"];


arguments;
arguments = [NSArray arrayWithObjects:@"abc", pid, nil];
[task setArguments: arguments];




//
dataInput = [stringInput dataUsingEncoding:NSUTF8StringEncoding];



outputPipe;
outputPipe = [NSPipe pipe];
[task setStandardOutput: outputPipe];

//
inputPipe;
inputPipe = [NSPipe pipe];
[task setStandardInput:inputPipe];


taskOutput;
taskOutput = [outputPipe fileHandleForReading];

//
taskInput;
taskInput = [inputPipe fileHandleForWriting];



[task launch];


[[[task standardInput] fileHandleForWriting] writeData:dataInput];
close([taskInput fileDescriptor]);


dataOutput;
dataOutput = [taskOutput readDataToEndOfFile];




NSString *stringOutput;
stringOutput = [[NSString alloc] initWithData: dataOutput encoding: NSUTF8StringEncoding];
NSLog (@"GDB Output:\n%@", stringOutput);

//NSLog(@"GDB Input:\n@", stringInput);





//[string release];
[task release];
[arguments release];

textView = [[UITextView alloc]initWithFrame:CGRectMake(8,17,330,440)];


textView.editable=NO;
textView.scrollEnabled=YES;
[self.view addSubview:textView];

textView.text = [textView.text stringByAppendingString:stringOutput];

    [super viewDidLoad];

}

IOS Simulator上的输出如下所示(x86寄存器)

enter image description here

实际设备(iPhone)上的输出如下所示:

enter image description here

在iPhone上运行时的构建输出如下所示:

RE:Notice: Launching: com.apple.gdb
abc: No such file or directory
//420: No such file or directory
Unable to access task for process-id 420: (os/kern) failure.
The program has no registers now.
2011-08-29 09:10:05.923 TableViewController_09[421:507] GDB Output:
GNU gdb 6.3.50.20050815-cvs (Fri May 20 08:08:42 UTC 2011)
Copyright 2004 Free Software Foundation, Inc.
GDB is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.
Type "show copying" to see the conditions.
There is absolutely no warranty for GDB.  Type "show warranty" for details.
This GDB was configured as "--host=arm-apple-darwin9 --target="...
(gdb) (gdb) 

作为旁注,我甚至试图添加参数-arch armv7 *。它仍然无法附加到指定的进程。

编辑:我可能已经找到了困境的来源。当我尝试通过应用程序在我的iPhone中调用gdb时,这显示在控制台中:

Sep  8 11:13:26 unknown sandboxd[2138] <Notice>: gdb(2137) deny mach-priv-task-port

Process:         gdb [2137]
Path:            /usr/bin/gdb
Load Address:    0x1000
Identifier:      gdb
Version:         ??? (1.0)
Code Type:       ARM (Native)
Parent Process:  TableViewController_09 [2135]

Date/Time:       2011-09-08 11:13:25.948 +0800
OS Version:      iPhone OS 4.3.3 (8J2)
Report Version:  104

Backtrace:
0   libsystem_kernel.dylib          0x36223c8c task_for_pid + 8
1   gdb                             0x001e4428 macosx_child_attach + 44 (macosx-nat-inferior.c:1781)
2   gdb                             0x00082f18 attach_command + 116 (infcmd.c:3089)
3   gdb                             0x000a3788 catch_command_errors + 100 (exceptions.c:540)
4   gdb                             0x000a53e4 captured_main + 2632 (main.c:888)
5   gdb                             0x000a3838 catch_errors + 104 (exceptions.c:525)
6   gdb                             0x000a4988 gdb_main + 56 (main.c:1033)
7   gdb                             0x0000224c main + 40 (gdb.c:36)
8   gdb                             0x0000217c _start + 312
9   gdb                             0x00002018 start + 24
10  gdb                             0x001e3dac macosx_lookup_task + 1596 (macosx-nat-inferior.c:1522)

Binary Images:
    0x1000 -   0x2fbf5b +gdb arm  /usr/bin/gdb
0x36214000 - 0x3622bfff  libsystem_kernel.dylib armv7  <a06ec84e53bf32098b63c0caebdb45b6> /usr/lib/system/libsystem_kernel.dylib

如果有人知道解决这个问题,请分享。我一直在寻找解决方案几周无济于事......

3 个答案:

答案 0 :(得分:1)

除非您越狱设备,否则无法在设备上运行gdb

答案 1 :(得分:1)

终于找到了解决它的方法。我所要做的就是将我的应用程序安装到iPhone上的/ Application文件夹中并设置它。这样,它将以root权限运行,因此可以在Apple的沙箱限制之外运行。

答案 2 :(得分:0)

我发现只需将可执行文件移动到/ Applications目录本身,然后将其sym链接回沙箱,也可以正常工作