Question

我想构造一个包含未知行数和2列数组的结构

之类的东西

struct s
{
     cinst char*** s;
}
const char* str1[][2] = {"1","2",
                        "3","4",
                        "5","6"};
s s1 = {str1};
const char* str2[][2] = {"1","2",
                        "3","4"};

s s2 = {str2};

代码编译失败。如何解决问题？

Answer 1

除了拼写错误cinst和丢失的分号和假设（不让我们知道）s和struct s属于同一类型

您的问题是str1和结构成员s的类型不兼容

str1的类型为const char*[][2]
struct成员的类型为const char***

强制编译器假定str1类型const char ***解决了您的直接问题，即程序编译并“正常工作”，但您确实需要了解数组不是指针和指针不是数组。请参阅c-faq site的第6部分。

struct s
{
     const char*** s;
};
const char* str1[][2] = {"1","2",
                        "3","4",
                        "5","6"};
struct s s1 = {(const char ***)str1};
const char* str2[][2] = {"1","2",
                        "3","4"};

struct s s2 = {(const char ***)str2};

Answer 2

嗯，它不是C.（并且缺少分号）

struct s {...};不引入类型“s”，不是typedef。例如你不能使用： struct s {...}; s my_thing; （即使你添加了缺少的分号）也许你在混淆C和C ++？

Answer 3

struct s
{
    cinst char** s;
};
const char str1[][2] = {"1","2",
                "3","4",
                "5","6"};
s s1 = {str1};
const char str2[][2] = {"1","2",
                "3","4"};

s s2 = {str2};

删除第三个间接/解除引用将解决此问题。

C“通用”结构构建

3 个答案: