我正在尝试创建一个函数,该函数从Wordpress自定义字段调用值(“_videourl”表示YouTube视频网址),然后使用PHP修剪将其缩小为YouTube视频ID。我发现了一个javascript函数,可以将URL减少到ID,但我不知道我怎么能将它转换成php(下面的函数):
function youtubeIDextract(url)
{
var youtube_id;
youtube_id = url.replace(/^[^v]+v.(.{11}).*/,"$1");
return youtube_id;
}
这个PHP函数将在循环中使用,所以我想我将不得不使用变量,但我真的只是一个菜鸟,所以我不知道该怎么做。任何人都可以通过分享他们的编码专业知识来帮助我创建PHP函数吗?
修改:解决
经过一些实验,我找到了解决方案。我想返回并发布它,以便其他有需要的人可以从某个地方开始。
function getYoutubeId($ytURL)
{
$urlData = parse_url($ytURL);
//echo '<br>'.$urlData["host"].'<br>';
if($urlData["host"] == 'www.youtube.com') // Check for valid youtube url
{
$ytvIDlen = 11; // This is the length of YouTube's video IDs
// The ID string starts after "v=", which is usually right after
// "youtube.com/watch?" in the URL
$idStarts = strpos($ytURL, "?v=");
// In case the "v=" is NOT right after the "?" (not likely, but I like to keep my
// bases covered), it will be after an "&":
if($idStarts === FALSE)
$idStarts = strpos($ytURL, "&v=");
// If still FALSE, URL doesn't have a vid ID
if($idStarts === FALSE)
die("YouTube video ID not found. Please double-check your URL.");
// Offset the start location to match the beginning of the ID string
$idStarts +=3;
// Get the ID string and return it
$ytvID = substr($ytURL, $idStarts, $ytvIDlen);
return $ytvID;
}
else
{
//echo 'This is not a valid youtube video url. Please, give a valid url...';
return 0;
}
}
答案 0 :(得分:13)
我必须为几周前编写的PHP类处理这个问题,并最终得到一个匹配任何类型字符串的正则表达式:有或没有URL方案,有或没有子域,youtube.com URL字符串,youtu .be URL字符串并处理所有类型的参数排序。您可以查看at GitHub或只是复制并粘贴下面的代码块:
/**
* Check if input string is a valid YouTube URL
* and try to extract the YouTube Video ID from it.
* @author Stephan Schmitz <eyecatchup@gmail.com>
* @param $url string The string that shall be checked.
* @return mixed Returns YouTube Video ID, or (boolean) false.
*/
function parse_yturl($url)
{
$pattern = '#^(?:https?://)?(?:www\.)?(?:youtu\.be/|youtube\.com(?:/embed/|/v/|/watch\?v=|/watch\?.+&v=))([\w-]{11})(?:.+)?$#x';
preg_match($pattern, $url, $matches);
return (isset($matches[1])) ? $matches[1] : false;
}
要解释正则表达式,这是一个溢出的版本:
/**
* Check if input string is a valid YouTube URL
* and try to extract the YouTube Video ID from it.
* @author Stephan Schmitz <eyecatchup@gmail.com>
* @param $url string The string that shall be checked.
* @return mixed Returns YouTube Video ID, or (boolean) false.
*/
function parse_yturl($url)
{
$pattern = '#^(?:https?://)?'; # Optional URL scheme. Either http or https.
$pattern .= '(?:www\.)?'; # Optional www subdomain.
$pattern .= '(?:'; # Group host alternatives:
$pattern .= 'youtu\.be/'; # Either youtu.be,
$pattern .= '|youtube\.com'; # or youtube.com
$pattern .= '(?:'; # Group path alternatives:
$pattern .= '/embed/'; # Either /embed/,
$pattern .= '|/v/'; # or /v/,
$pattern .= '|/watch\?v='; # or /watch?v=,
$pattern .= '|/watch\?.+&v='; # or /watch?other_param&v=
$pattern .= ')'; # End path alternatives.
$pattern .= ')'; # End host alternatives.
$pattern .= '([\w-]{11})'; # 11 characters (Length of Youtube video ids).
$pattern .= '(?:.+)?$#x'; # Optional other ending URL parameters.
preg_match($pattern, $url, $matches);
return (isset($matches[1])) ? $matches[1] : false;
}
答案 1 :(得分:0)
假设正则表达式是正确的,您可以使用preg_replace
$youtubeId = preg_replace('/^[^v]+v.(.{11}).*/', '$1', $url);
您可能也会对str_replace
或substr
感兴趣。
答案 2 :(得分:0)
我找到的最佳解决方案;
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margin-top: 0;
}
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margin-bottom: 0;
margin-top: 0;
}