Question

基本上，我想为一个更大的项目创建一个简单的函数，这实际上最终将作为一个处理我所有库存的Header文件。任何人，我只是希望它能够从.csv文件格式读取/拉取/输入数据......或者如果更容易使这个功能起作用，我甚至可以做.txt，只要我能在MS Excel中打开并编辑项目并添加新项目，当函数运行时，它将打开“Example.csv”，例如，该函数将查找第1列中的单元格 - 'sSwordName'，它将拉取该行中的数据，关闭该单元格，在所有输入中完全排除第一列...它将它组合在一起，或者为了将其分配给该变量，它可能需要做什么。请参阅Code.h（评论）以查看我的源代码问题。

Code.h -

#include "stdafx.h"
#include <string>
#include <fstream>
#include <sstream>
#include <iostream>
#include <vector>
using namespace std;

char sSwordName[100][25] = {};
int sSwordLvlR[100] = {};

vector<string> split_at_commas(const string & row)
{
    vector<string> res;
    istringstream buf(row);
    string s;
    while (getline(buf, s, ','))
        res.push_back(s);
    return res;
    system("pause");
}

/* Question 1: Where & How do I properly add 'ifstream wInv("Example.csv");' in order to Load the CSV file it is reading? */
/* Question 2: Line 38 & 46. */
/* Question 3: Line 39 & 47 */

int main()
{
    int i = 1;

    string line;
    string row;
    vector<string> values = split_at_commas(line);
    if (values[0] == "sSwordName")
    {
        for(int i = 1; i < values.size(); ++i);
        {
            /*int i error: Object must have a pointer-to-object type*/ 
            sSwordName[100][25][i - 1] = /*How do I convert string to char?*/(vector[i]);
        }
    }
    else if (values[1] == "sSwordLvlR")
    {
        for(int i = 1; i < values.size(); ++i);
        {
            /*int i error: Object must have a pointer-to-object type*/
            sSwordLvlR[i - 1] = /*How do I Convert string to int?*/(vector[i]);
        }
    }
}
/* Question 4: Is there anything else that is wrong in this? If so, how would I fix it */

Example.csv -

sSwordName,Wooden Shortsword,Bronze Shortsword,Iron Shortsword,Steel Shortsword,Titanium Shortsword
    sSwordLvlR,1,3,5,6,10

有关CSV的更多信息：

sSwordName,Wooden Shortsword,Bronze Shortsword,Iron Shortsword,Steel Shortsword,Titanium Shortsword
sSwordLvlR,1,3,5,6,10

^不是我可以格式化它的唯一方式，为方便起见我可以做这样的事情（下面，E2.csv）。如果更容易制作功能，请执行。;

sSwordName,"Wooden Shortsword","Bronze Shortsword","Iron Shortsword","Steel Shortsword","Titanium Shortsword"
sSwordLvlR,"1,","3,","5,","6,","10,"

我甚至可以用这种方式格式化它;

sSwordName,"{"Wooden Shortsword","Bronze Shortsword","Iron Shortsword","Steel Shortsword","Titanium Shortsword"};
sSwordLvlR,"{1,3,5,6,10};"

再一次，我非常感谢任何帮助。我在高级中感谢你！ -Leaum

从CSV文件到可变数组的Visual Studio C ++数据

0 个答案: