Question

我将JSON作为NSString：

[{"bus_number":"1","created_at":"2011-08-15T23:07:52Z","id":1,"model":"Setra","registar_number":"123456","seats":50,"tour_id":1,"updated_at":"2011-08-15T23:07:52Z"},{"bus_number":"2","created_at":"2011-08-15T23:07:52Z","id":2,"model":"Mercedes","registar_number":"2234","seats":60,"tour_id":1,"updated_at":"2011-08-15T23:07:52Z"}]

我正在尝试将此NSString转换为NSDictionary。

当我使用时：

NSDictionary *sourceDictionary = [[response bodyAsString] objectFromJSONString];

我得到像这样的NSDictionary：

(
    {
    "bus_number" = 1;
    "created_at" = "2011-08-15T23:07:52Z";
    id = 1;
    model = Setra;
    "registar_number" = 123456;
    seats = 50;
    "tour_id" = 1;
    "updated_at" = "2011-08-15T23:07:52Z";
},
    {
    "bus_number" = 2;
    "created_at" = "2011-08-15T23:07:52Z";
    id = 2;
    model = Mercedes;
    "registar_number" = 2234;
    seats = 60;
    "tour_id" = 1;
    "updated_at" = "2011-08-15T23:07:52Z";
}

）

但是，这个NSDictionary有一个问题，我无法访问他们的元素，有些元素不是NSStrings（就像模型一样）。

如何使用NSStrings将JSONString转换为NSDictionary？

修改

当我尝试使用以下命令登录控制台时：

for (id key in sourceDictionary) {
            NSLog(@"key: %@, value: %@", key, [sourceDictionary objectForKey:key]);
        }

我得到例外：

-[__NSArrayM objectForKey:]: unrecognized selector sent to instance 0x1c3a50

Answer 1

如果你是从RestKit那里得到的，看起来就像你一样，你可以这样做：

NSMutableDictionary *myDictionary = [response.body mutableObjectFromJSONData];

通过这种方式，您可以将二进制数据拉入原始状态，并且可以避免在流程中来回转换为字符串的不必要（且代价高昂）。此外，我规定了可变性，因为当你得到数据时，你很可能想要操纵或捣乱数据......再次，来自JSONKit超类的非可变对象和可变对象之间的转换涉及成本......所以从一开始就加入变数，你就节省了一些时间。

Answer 2

这些实际上是NSStrings，当你把它们打印到控制台时它们只是没有引号。

JSonKit反序列化问题

2 个答案: