Question

我想使用table_1选项中的（id_1）id数组来获取table_2中id_2 = id_1的所有行

  SELECT field_b
  FROM table_2
  WHERE id_2 IN (
         SELECT id_1 FROM table_1 WHERE field_a = 1234
  );

以下是我的表格示例供参考：

  mysql> select * from table_1;
    +-------+---------+
    |  id_1 | field_a |
    +-------+---------+
    |     1 |    1234 |
    +-------+---------+
    |     2 |    1234 |
    +-------+---------+


mysql> select * from table_2;
+---------+---------+
|    id_2 | field_b |
+---------+---------+
|     1   |  5678   |
+-------+-----------+
|     2   |  0013   |
+-------+-----------+

Answer 1

INNER JOIN对你来说效果会好吗？

SELECT field_b
FROM table_2
INNER JOIN table_1
    ON table_2.id_2 = table_1.id_1
WHERE table_2.field_a=1234

Answer 2

我不知道这是否是您所需要的：

SELECT * FROM table_2 t2
INNER JOIN table_1 t1
ON t2.id_2 = t1.id_1
WHERE t1.field_a = 1234

Answer 3

另一种选择：

SELECT field_b
FROM table_2
WHERE EXISTS 
      ( SELECT * 
        FROM table_1 
        WHERE field_a = 1234
          AND table_2.id_2 = table_1.id_1
      )

MySQL子查询结果数组

3 个答案: