我希望你能帮助我,我有这样的结构:
- root A
-child_A1
-child_A1_1
-child_A1_2
-child_A1_3
-child_A2
-child_A2_1
-child_A2_2
-child_A2_3
- root B
- child_B1
-child_B1_1
-child_B1_2
-child_B1_3
但是当我在TreeGrid中显示数据时,它显示如下:
- root A
-child_A1
-child_A2
-child_A1_1
- root B
- child_B1
-child_B1_1
-child_B1_2
-child_B1_3
-child_A1_2
-child_A1_3
-child_A2_1
-child_A2_2
-child_A2_3
有人知道为什么.. ???请帮助,我搜索有关此错误的信息,但没有运气....
这是我的JavaScript:
<script type="text/javascript">
$(document).ready(function () {
var lastsel;
$(function () {
jQuery('#tree').jqGrid({
url: '/Ubicacion/TreeGrid/',
datatype: 'json',
height: 250,
colNames: ['Nombre', 'Descripcion'],
colModel: [
{ name: 'Nombre', index: 'Nombre', width: 100, sortable: true, editable: true, edittype: "text"},
{ name: 'Descripcion', index: 'Descripcion', width: 80, editable: true, edittype: "text" }
],
caption: 'Listado de Ubicaciones',
treeGridModel: 'adjacency',
sortname: 'Nombre',
loadonce: true,
height: 'auto',
width: '500',
pager: "#pager",
treeGrid: true,
ExpandColumn: 'Id',
ExpandColClick: true,
});
});
});
这是我用来生成json字符串的服务器端函数:
public ActionResult TreeGrid(string sidx, string sord, int? page, int? rows)
{
List<Ubicacion> ubicacion = new List<Ubicacion>();
ubicacion = UbicacionRepository.GetAll().ToList<Ubicacion>();
int pageIndex = Convert.ToInt32(page) - 1;
int totalrecords = ubicacion.Count();
JsonResult json = new JsonResult();
json.JsonRequestBehavior = JsonRequestBehavior.AllowGet;
json.Data = new
{
sidx = "Nombre",
sord = "asc",
page = page,
records = totalrecords,
rows = (from ubi in ubicacion
select new
{
cell = new string[]
{
ubi.Nombre,
ubi.Descripcion,
ubi.Nivel.ToString(),
ubi.IdPadre == 0 ? "null" : ubi.IdPadre.ToString(),
ubi.Nivel < 2 ? "false" : "true",
"false",
"true"
}
})
};
return json;
}
这是json生成的:
{"total":1,"page":null,"records":18,"rows":[
{"cell":["Parent A","ubicacion","0","null","false","false","true"]},
{"cell":["Child A1","ubicacion","1","1","false","false","true"]},
{"cell":["Child A2","ubicacion","1","1","false","false","true"]},
{"cell":["Child A1_1","ubicacion","2","2","true","false","true"]},
{"cell":["Parent B","ubicacion","0","null","false","false","true"]},
{"cell":["Child B1","ubicacion","1","5","false","false","true"]},
{"cell":["Child B1_1","ubicacion","2","6","true","false","true"]},
{"cell":["Child B1_2","ubicacion","2","6","true","false","true"]},
{"cell":["Child B1_3","ubicacion","2","6","true","false","true"]},
{"cell":["Child A1_2","ubicacion","2","2","true","false","true"]},
{"cell":["Child_A1_3","ubicacion","2","2","true","false","true"]},
{"cell":["Child A2_1","ubicacion","2","3","true","false","true"]},
{"cell":["Child A2_2","ubicacion","2","3","true","false","true"]},
{"cell":["Child A2_3","ubicacion","2","3","true","false","true"]}
]}
答案 0 :(得分:1)
我明白了!你需要递归地命令列表,因为它按照你从数据库中提取的确切顺序进行渲染..
private static List<MENU> Listado = new List<MENU>();
private static List<MENU> lstOrdenada = new List<MENU>();
public List<MENU> MenuRecursivo()
{
//the whole list of MENU
Listado = (from m in db.MENU where m.men_eliminado == "N" select m).ToList();
// a list where we'll put the ordered items
lstOrdenada = new List<MENU>();
foreach (MENU item in Listado.Where(x => x.ID_MENU == x.id_menu_padre).ToList()) // in my case, only the root items match this condition
{
lstOrdenada.Add(item);
GMenuHijo(item.ID_MENU, ref lstOrdenada);
}
return lstOrdenada;
}
`
然后,对于每个根项,递归地找到下一个级别:
private static void GMenuHijo(int idPadre, ref List<MENU> lst)
{
List<MENU> listado2 = Listado.Where(x => x.id_menu_padre == idPadre && x.ID_MENU != x.id_menu_padre).ToList();
if (listado2.Count > 0)
{
foreach (MENU item in listado2)
{
lst.Add(item);
GMenuHijo(item.ID_MENU, ref lst);
}
}
}
答案 1 :(得分:1)
我遇到了同样的问题。似乎jqGrid期望数据已经在树结构中排序(即它不在客户端执行排序)但我可能错了。下面是我创建的一些扩展,用于执行包含具有指定ID和父ID属性的对象的通用IEnumerable的树类。父ID属性中的对象将为null放置在根目录中。
public static class TreeSortExtensions
{
public static IEnumerable<T> OrderByTreeStructure<T>(
this IEnumerable<T> source,
string objectIDProperty,
string parentIDPropery)
{
IEnumerable<T> result = source;
if (!string.IsNullOrEmpty(objectIDProperty) && !string.IsNullOrEmpty(parentIDPropery))
{
result = source.GetChildrenOfTreeNode(null, objectIDProperty, parentIDPropery, true);
}
return result;
}
public static IEnumerable<T> GetChildrenOfTreeNode<T>(
this IEnumerable<T> source,
object parent,
string property,
string parentProperty,
bool recurse)
{
if (!string.IsNullOrEmpty(property) && !string.IsNullOrEmpty(parentProperty))
{
IEnumerable<T> children;
if (parent == null)
{
children = source.Where(x => x.GetPropertyValue(parentProperty) == null);
}
else
{
var parentIDValue = parent.GetPropertyValue(property);
children = source.Where(x => (x.GetPropertyValue(parentProperty) != null) &&
(x.GetPropertyValue(parentProperty).Equals(parentIDValue)));
}
foreach (T child in children)
{
yield return child;
if (recurse)
{
var grandChildren = source.GetChildrenOfTreeNode(child, property, parentProperty, true).ToArray();
foreach (T grandchild in grandChildren)
{
yield return grandchild;
}
}
}
}
}
public static object GetPropertyValue(this object obj, string property)
{
return obj.GetType().GetProperty(property).GetValue(obj, null);
}
}
请注意,“parent”参数的类型为object而不是T.这允许将null作为根级别对象的父级传递。
用法:
var result1 = someEnumerable.OrderByTreeStructure("SomeIDProperty", "SomeParentIDProperty");
var result2 = someDbContext.SomeTable.OrderByTreeStructure("ID", "ParentID");