查看具有相似标题的问题,并没有足够接近这个查询的工作。我知道这可能是相当简单的事情。
实际的查询是:
select entries.id, entry_id, user_id, person_id, campaign_id, mood_id, entries.created, deleted_date, entries.modified, entry_type, walking_hash
from entries, users
where users.id = entries.user_id and users.is_deleted = 0 and entries.is_deleted = 0
and entries.entry_type in ('xyz', 'abc', 'def', 'lmno')
为了得到计数我试过了:
select count(entries.id, entry_id, user_id, person_id, campaign_id, mood_id, entries.created, deleted_date, entries.modified, entry_type, walking_hash)
from entries, users
where users.id = entries.user_id and users.is_deleted = 0 and entries.is_deleted = 0 and entries.entry_type in ('xyz', 'abc', 'def', 'lmno')
但是会抛出非描述性错误并且不会运行。
答案 0 :(得分:1)
你到底想要计算什么?只是行数?使用COUNT(*)
。使用COUNT(column)
计算此列中的所有非NULL值。
然后查询将只返回一行,即计数。
select count(*) as count
from entries, users
where users.id = entries.user_id and users.is_deleted = 0 and entries.is_deleted = 0
and entries.entry_type in ('xyz', 'abc', 'def', 'lmno')
答案 1 :(得分:0)
select count(1)
from entries, users
where users.id = entries.user_id and users.is_deleted = 0 and entries.is_deleted = 0 and entries.entry_type in ('xyz', 'abc', 'def', 'lmno')
答案 2 :(得分:0)
你应该使用简单的
Select count(entries.id) ....