Question

我从视图中提取并使用此查询。

（它意味着传递一个节点id，并返回所有具有此节点id的节点作为节点引用）

function jsonview_node_update($node){
  if ($node->type == "company") {
    $query = "SELECT DISTINCT node.title AS node_title, node.nid AS nid
              FROM {node} node
              LEFT JOIN field_data_field_campaigncompany ON node.nid = field_data_field_campaigncompany.entity_id AND (field_data_field_campaigncompany.entity_type = node AND field_data_field_campaigncompany.deleted = 0)
              WHERE (( (node.status = '1') AND (field_data_field_campaigncompany.field_campaigncompany_nid IN  ('".$node->nid."')) AND (node.type IN  ('campaign')) ))";
    $result = db_query($query);
    file_put_contents('/tmp/ref.txt',json_encode($result));
  }

正在返回

PDOException: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'node' in 'on clause': SELECT DISTINCT node.title AS node_title, node.nid AS nid FROM {node} node LEFT JOIN field_data_field_campaigncompany ON node.nid = field_data_field_campaigncompany.entity_id AND (field_data_field_campaigncompany.entity_type = node AND field_data_field_campaigncompany.deleted = 0) WHERE (( (node.status = '1') AND (field_data_field_campaigncompany.field_campaigncompany_nid IN ('14')) AND (node.type IN ('campaign')) )); Array ( ) in jsonview_node_update() (line 224 of /jsonview.module).

不确定这里有什么问题..我已尝试过关系和其他几个模块而且没有人真正做到这一点

Answer 1

（在问题编辑中回答。转换为社区维基回答。请参阅Question with no answers, but issue solved in the comments (or extended in chat)）

OP写道：

解决：

function jsonview_node_update($node){
  if ($node->type == "company") {
    $query = "SELECT DISTINCT title, nid
              FROM {node} node
              LEFT JOIN field_data_field_campaigncompany ON node.nid = field_data_field_campaigncompany.entity_id AND (field_data_field_campaigncompany.entity_type = 'node' AND field_data_field_campaigncompany.deleted = 0)
              WHERE (( (node.status = '1') AND (field_data_field_campaigncompany.field_campaigncompany_nid IN  ('".$node->nid."')) AND (node.type IN  ('campaign')) ))";
 //   $query = "SELECT nid, title FROM {node}";
   $result = db_query($query);
  //  $result = db_query("SELECT nid, title FROM {node}");
    foreach ($result as $record) {
       file_put_contents('/tmp/ref.txt',json_encode($record),FILE_APPEND);
  // Do something with each $record
}

  }
}

用于drupal 7模块的sql查询

1 个答案: