Question

在下面的MySQL存储函数调用中，我不想手动输入lat long坐标，而是想从另一个表中选择一个多边形进行测试。我在解决语法问题上遇到了问题。

SELECT IS_POINT_IN_POLYGON(
POINTFROMTEXT( CONCAT( 'POINT(', latitude, ' ', longitude, ')' ) ) , POLYFROMTEXT( 'POLYGON((43.40930419213147, -72.5537109375
43.40884544242924, -72.53695249557495
43.38754804789373, -72.5437331199646
43.378580946950244, -72.58398771286011
43.40930419213147, -72.5537109375 ))' )
)AS result, latitude, longitude
FROM sport
WHERE sport_type = 'lacrosse' AND IS_POINT_IN_POLYGON(
POINTFROMTEXT( CONCAT( 'POINT(', latitude, ' ', longitude, ')' ) ) , POLYFROMTEXT( 'POLYGON((43.40930419213147, -72.5537109375
43.40884544242924, -72.53695249557495
43.38754804789373, -72.5437331199646
43.378580946950244, -72.58398771286011
43.40930419213147, -72.5537109375))' )
) = 1;

所以，我想删除 43.40930419213147，-72.5537109375 43.40884544242924，-72.53695249557495 43.38754804789373，-72.5437331199646 43.378580946950244，-72.58398771286011 43.40930419213147，-72.5537109375

相反，我想使用这个选择语句：

SELECT neighborhood_polygon FROM `neighborhood_shapes` WHERE neighborhood="XYZ neighborhood"

我有多边形存储在neighborhood_shapes中。其结构如下：

neighborhood_index smallint（3）
邻居varchar（50）
neighborhood_polygon（几何形状）

其他信息：

IS_POINT_IN_POLYGON的调用方式如下：IS_POINT_IN_POLYGON（p POINT，poly POLYGON）

有什么建议吗？

Answer 1

尝试这样做。

... POLYFROMTEXT(
    (SELECT neighborhood_polygon 
      FROM neighborhood_shapes 
      Where neighborhood = "XYZ neighborhood") as coords)

在MySQL函数调用中使用Select语句

1 个答案: