Question

我需要在objective-c中将十六进制字符串转换为二进制形式，有人可以指导我吗？例如，如果我有一个十六进制字符串7fefff78，我想将其转换为1111111111011111111111101111000？

BR， Suppi

Answer 1

很好的递归解决方案......

NSString *hex = @"49cf3e";
NSUInteger hexAsInt;
[[NSScanner scannerWithString:hex] scanHexInt:&hexAsInt];
NSString *binary = [NSString stringWithFormat:@"%@", [self toBinary:hexAsInt]];

-(NSString *)toBinary:(NSUInteger)input
{
    if (input == 1 || input == 0)
        return [NSString stringWithFormat:@"%u", input];
    return [NSString stringWithFormat:@"%@%u", [self toBinary:input / 2], input % 2];
}

Answer 2

只需逐个转换每个数字：0 -> 0000，7 -> 0111，F -> 1111等。一个小的查找表可以使这个非常简洁。

作为另一个基地的力量的数字基础的美丽： - ）

Answer 3

如果您需要前导零，例如18返回00011000而不是11000

-(NSString *)toBinary:(NSUInteger)input strLength:(int)length{
        if (input == 1 || input == 0){

         NSString *str=[NSString stringWithFormat:@"%u", input];
            return str;
        }
        else {
            NSString *str=[NSString stringWithFormat:@"%@%u", [self toBinary:input / 2 strLength:0], input % 2];
            if(length>0){
                int reqInt = length * 4;
                for(int i= [str length];i < reqInt;i++){
                    str=[NSString stringWithFormat:@"%@%@",@"0",str];
                }
            }
            return str;
        }  
}
 NSString *hex = @"58";
 NSUInteger hexAsInt;
 [[NSScanner scannerWithString:hex] scanHexInt:&hexAsInt];
 NSString *binary = [NSString stringWithFormat:@"%@", [self toBinary:hexAsInt strLength:[hex length]]];
NSLog(@"binario %@",binary);

Answer 4

我同意kerrek SB的回答并尝试了这一点。它的工作对我来说。

+(NSString *)convertBinaryToHex:(NSString *) strBinary
{
    NSString *strResult = @"";
    NSDictionary *dictBinToHax = [[NSDictionary alloc] initWithObjectsAndKeys:
                                  @"0",@"0000",
                                  @"1",@"0001",
                                  @"2",@"0010",
                                  @"3",@"0011",

                                  @"4",@"0100",
                                  @"5",@"0101",
                                  @"6",@"0110",
                                  @"7",@"0111",

                                  @"8",@"1000",
                                  @"9",@"1001",
                                  @"A",@"1010",
                                  @"B",@"1011",

                                  @"C",@"1100",
                                  @"D",@"1101",
                                  @"E",@"1110",
                                  @"F",@"1111", nil];

    for (int i = 0;i < [strBinary length]; i+=4)
    {
        NSString *strBinaryKey = [strBinary substringWithRange: NSMakeRange(i, 4)];
        strResult = [NSString stringWithFormat:@"%@%@",strResult,[dictBinToHax valueForKey:strBinaryKey]];
    }
    return  strResult;
}

如何将Hex转换为二进制iphone

4 个答案: