在echo引用字符串中使用PHP变量？

Question

如何在echo ""中使用ucwords（$ firstname）？即

<?php
$firstname = "john";
$surname = "smith";
echo "Welcome ucwords($firstname) ucwords($surname)";
?>

Answer 1

<?php
$firstname = "john";
$surname = "smith";
echo "Welcome " . ucwords($firstname) . " " .  ucwords($surname);
?>

喜欢这个。

Answer 2

echo "Welcome" .  ucwords($firstname) . " " . ucwords($surname);

编辑：

替代模式：

$firstname = ucwords($firstname);
$surname = ucwords($surname);

echo 'Welcome $firstname $surname';

Answer 3

像这样：

<?php
$firstname = "john";
$surname = "smith";
echo "Welcome " . ucwords($firstname) . " " . ucwords($surname);
?>

或者这个：

<?php
$firstname = "john";
$surname = "smith";
$format = "Welcome %s %s";
printf($format, ucwords($firstname), ucwords($surname));
?>

Answer 4

echo "Welcome " . ucwords($firstname) . " " . ucwords($surname);

Answer 5

这是极端的hacky，但你可以使用变量函数：

$uc = 'ucwords';
$firstname = 'fred';
$lastname = 'jones';

echo "Welcome {$uc($firstname)} {$uc($lastname)}";

Answer 6

PHP脚本：

<?php
$firstname = 'john';
$surname = 'smith';
//Use of single quote instead double is an optimize way
echo 'Welcome '.ucwords($firstname).' '.ucwords($surname);
?>

<强>输出：

欢迎John Smith

<强> Reference