我的视图中有几种不同的形式。第一种形式具有填充多选字段的搜索字段,并且当用户在搜索字段中键入其查询时,发送AJAX调用以带来与查询匹配的所有记录。然后,用户从第一个多选字段中选择选项,然后单击“添加”将它们移动到另一个多选框
这样可以正常工作,但是当表单提交时,我会收到一条错误 “选择有效的选择.1不是可用的选择之一。” 我已经尝试在接收形式init之后设置选项,但这似乎不起作用。
我的表格:
class SiteCoordinatorForm(forms.ModelForm):
selected_studies = forms.MultipleChoiceField(required = False)
site = forms.ChoiceField(required = False)
studies = forms.MultipleChoiceField(required = False)
study_search = forms.CharField(max_length = 50, required = False)
def __init__(self, *args, **kwargs):
super(SiteCoordinatorForm, self).__init__(*args, **kwargs)
if args:
study_list = []
query_dict = args[0]
self.fields['selected_studies'].choices = [(int(x), x) for x in query_dict.getlist('selected_studies')]
self.fields['site'].choices = [(x.pk, "%s (%s)" % (x.primary_name, x.primary_number)) for x in Site.objects.all().order_by('primary_name')]
class Meta:
model = SiteCoordinator
exclude = ('studies', 'site', 'selected_studies')
我的AJAX功能填充框:
def search_studies(request):
return_data = {}
studies = []
make_query = lambda terms, fieldname: reduce(lambda x, y: x & Q(**{fieldname + '__icontains': y}), terms, Q())
if 'search_text' in request.POST:
terms = request.POST['search_text'].split()
for rec in Study.objects.filter(make_query(terms, 'name')):
studies.append({
'study': {'id': rec.id, 'name': rec.name, 'number': rec.id}
})
response = {'status': 'success', 'count': len(studies), 'studies': studies}
return HttpResponse(simplejson.dumps(response), mimetype="application/json")
填充MultiSelectBox的功能:
function show_results(data, status_code, request){
recs = data.studies;
var select_box = document.getElementById('id_studies');
select_box.options.length = 0;
for (var index = 0; index < recs.length; index ++){
select_box.options[index] = new Option(recs[index].study.name,
recs[index].study.id,
false, false);
}
}
然后JQuery移动选择:
$('#add').click(function() {
$('#id_studies option:selected').remove().appendTo('#id_selected_studies');
return false;
});
$('#remove').click(function() {
$('#id_selected_studies option:selected').remove().appendTo('#id_studies');
return false;
});
答案 0 :(得分:4)
很明显,我们不希望对MultipleChoiceField
进行验证,但确实需要MultipleSelectWidget
,因此解决方案只是将字段更改为
studies = forms.CharField(widget=forms.SelectMultiple)
并在
中进行自己的验证def clean_studies(self):
...
答案 1 :(得分:0)
这是一个使用@AnuragUniyal提出的解决方案的例子,也回答了@ JohnLehmann的评论:
Routing.generate()
基本上我们将unicode字符串列表的字符串转换回应用class MyForm(forms.Form):
new_tags = forms.CharField(required=False, widget=forms.SelectMultiple)
def save(self, commit=True):
instance = super(MyForm, self).save(commit=commit)
for tag in eval(self.cleaned_data['new_tags']):
models.Tag.objects.get_or_create(name=tag)
return instance
的Python列表。