我的XML Schema中有一个元素定义如下:
<xs:complexType name="MyNumberCodeType">
<xs:sequence>
<xs:element name="Code" type="NumberCodeValueType" maxOccurs="unbounded" />
</xs:sequence>
</xs:complexType>
NumberCodeValueType为:
<xs:simpleType name="NumberCodeValueType">
<xs:restriction base="xs:int">
<xs:pattern value="[0-7]{7}"/>
</xs:restriction>
</xs:simpleType>
也就是说,我的号码可以从前导0开始。我无法修改此架构。我正在使用JAXB生成我的Java类。不幸的是,Code
元素的访问器将整数列表作为参数,这意味着所有前导0都被剥离(因为,据我所知,当使用整数时,无法在Java中保持前导0型)!
有什么方法可以解决这个问题吗?
感谢您的帮助!
答案 0 :(得分:34)
您可以执行以下操作:
<强>的NumberFormatter 强>
您可以通过编写自己的格式化程序来完成此操作:
package forum7182533;
public class NumberFormatter {
public static String printInt(Integer value) {
String result = String.valueOf(value);
for(int x=0, length = 7 - result.length(); x<length; x++) {
result = "0" + result;
}
return result;
}
public static Integer parseInt(String value) {
return Integer.valueOf(value);
}
}
XMLSchema(format.xsd)
然后,当您要从XML Schema生成类时:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="root">
<xs:complexType>
<xs:sequence>
<xs:element name="number" type="NumberCodeValueType" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:simpleType name="NumberCodeValueType">
<xs:restriction base="xs:int">
<xs:pattern value="[0-7]{7}" />
</xs:restriction>
</xs:simpleType>
</xs:schema>
<强> bindings.xml 强>
您将利用JAXB绑定文件来引用格式化程序:
<jxb:bindings xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:jxb="http://java.sun.com/xml/ns/jaxb" version="2.1">
<jxb:bindings schemaLocation="format.xsd">
<!--jxb:bindings node="//xs:simpleType[@name='NumberCodeValueType']" -->
<jxb:bindings node="//xs:element[@name='number']">
<jxb:property>
<jxb:baseType>
<jxb:javaType name="java.lang.Integer"
parseMethod="forum7182533.NumberFormatter.parseInt" printMethod="forum7182533.NumberFormatter.printInt" />
</jxb:baseType>
</jxb:property>
</jxb:bindings>
</jxb:bindings>
</jxb:bindings>
XJC致电
绑定文件在XJC调用中被引用为:
xjc -d out -p forum7182533 -b bindings.xml format.xsd
<强>适配器1 强>
这将导致创建XmlAdapter
以利用您的格式化程序:
package forum7182533;
import javax.xml.bind.annotation.adapters.XmlAdapter;
public class Adapter1
extends XmlAdapter<String, Integer>
{
public Integer unmarshal(String value) {
return (forum7182533.NumberFormatter.parseInt(value));
}
public String marshal(Integer value) {
return (forum7182533.NumberFormatter.printInt(value));
}
}
<强>根强>
XmlAdapter
将使用@XmlJavaTypeAdapter
注释从您的域对象中引用:
package forum7182533;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"number"
})
@XmlRootElement(name = "root")
public class Root {
@XmlElement(required = true, type = String.class)
@XmlJavaTypeAdapter(Adapter1 .class)
protected Integer number;
public Integer getNumber() {
return number;
}
public void setNumber(Integer value) {
this.number = value;
}
}
<强>演示强>
现在,如果您运行以下演示代码:
package forum7182533;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Root.class);
Root root = new Root();
root.setNumber(4);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(root, System.out);
}
}
<强>输出强>
您将获得所需的输出:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root>
<number>0000004</number>
</root>