我创建了一个简单的菜单栏,我不知道如何在可用空间中导入图像。
我的代码如下:
import java.awt.event.*;
import java.awt.*;
import javax.swing.*;
import java.io.IOException;
public class MyMenu extends JFrame {
JMenuBar menubar;
JMenu file, edit, contact, quit;
JMenuItem exit, open, search, delete, registration, informations;
public MyMenu() {
setLayout(new FlowLayout());
//___________________________ FILE __________________________________
menubar = new JMenuBar();
setJMenuBar(menubar);
file = new JMenu("Αρχείο");
menubar.add(file);
open = new JMenuItem("Άνοιγμα πελατολογίου");
file.add(open);
event e1 = new event(); // Compiler Error
open.addActionListener(e1);
//__________________________________ EDIT ____________________________
edit = new JMenu("Ενέργειες");
menubar.add(edit);
search = new JMenuItem("Αναζήτηση");
edit.add(search);
registration = new JMenuItem("Καταχώρηση");
edit.add(registration);
delete = new JMenuItem("Διαγραφή");
edit.add(delete);
//_________________________________ CONTACT __________________________
contact = new JMenu("Επικοινωνία");
menubar.add(contact);
informations = new JMenuItem("Πληροφορίες");
contact.add(informations);
//___________________________________QUIT_____________________________
quit = new JMenu("Έξοδος");
menubar.add(quit);
exit = new JMenuItem("Έξοδος");
quit.add(exit);
event e = new event(); // Compiler Error
exit.addActionListener(e);
}
public class MyEvent implements ActionListener {
public void actionPerformed(ActionEvent e) {
System.exit(0);
}
public void actionPerformed2(ActionEvent e1) {
final SimpleTableDemo a = new SimpleTableDemo(); // Compiler Error
javax.swing.SwingUtilities.invokeLater(new Runnable() {
public void run() {
a.createAndShowGUI();
}
});
}
}
public static void main(String[] args) throws IOException {
MyMenu gui = new MyMenu();
gui.getContentPane().add(panel); // Compiler Error
gui.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
gui.setSize(2400, 1900);
gui.setVisible(true);
}
}
它与班级Panel
有关?如何利用可用空间并使用图像?
答案 0 :(得分:4)
可以构建JMenuItem以显示图像。
ImageIcon icon = new ImageIcon("path_to_your_image");
JMenuItem item = new JMenuItem(icon);
答案 1 :(得分:4)
在// Compiler Error
JMenuBar
)
必修教程
2)Laying Out Components Within a Container
3)How to Write an Action Listener
5)最后将Image
设为JMenuBar BackGround
,你必须阅读一些内容
2D Graphics