Question

SortedList<string, int> list = new SortedList<string, int>;
list.Add("abc", 2);
list.Add("def", 3);

string index = list.GetIndex(2) ???????
Console.WriteLine(index);

我真的很困惑。如何使用索引的值

获取数组的索引

输出应为

ABC

解决方案：

使用SortedList公开的IndexOfValue方法，结合Linq扩展方法ElementAt（int index），所以：

string index = list.ElementAt(list.IndexOfValue(value)).Key;//output will be abc

- O ---

这也有效

string index = list.Keys.ElementAt<string>(list.IndexOfValue(2));

Answer 1

根据您的声明，输出应为abc，我认为您真的想要text，而不是index。要根据商品value获取商品的文字，只需执行以下操作：

SortedList<string, int> list = new SortedList<string, int>();
list.Add("abc", 2);
list.Add("def", 3);
string text = list.ElementAt(listz.IndexOfValue(2)).Key
Console.WriteLine(text);

Answer 2

关于SortedList.GetByIndex方法的MSDN文档：

using System;
using System.Collections;
public class SamplesSortedList  {

   public static void Main()  {

      // Creates and initializes a new SortedList.
      SortedList mySL = new SortedList();
      mySL.Add( 1.3, "fox" );
      mySL.Add( 1.4, "jumped" );
      mySL.Add( 1.5, "over" );
      mySL.Add( 1.2, "brown" );
      mySL.Add( 1.1, "quick" );
      mySL.Add( 1.0, "The" );
      mySL.Add( 1.6, "the" );
      mySL.Add( 1.8, "dog" );
      mySL.Add( 1.7, "lazy" );

      // Gets the key and the value based on the index.
      int myIndex=3;
      Console.WriteLine( "The key   at index {0} is {1}.", myIndex, mySL.GetKey( myIndex ) );
      Console.WriteLine( "The value at index {0} is {1}.", myIndex, mySL.GetByIndex( myIndex ) );

      // Gets the list of keys and the list of values.
      IList myKeyList = mySL.GetKeyList();
      IList myValueList = mySL.GetValueList();

      // Prints the keys in the first column and the values in the second column.
      Console.WriteLine( "\t-KEY-\t-VALUE-" );
      for ( int i = 0; i < mySL.Count; i++ )
         Console.WriteLine( "\t{0}\t{1}", myKeyList[i], myValueList[i] );
   }
}
/* 
This code produces the following output.

The key   at index 3 is 1.3.
The value at index 3 is fox.
    -KEY-    -VALUE-
    1    The
    1.1    quick
    1.2    brown
    1.3    fox
    1.4    jumped
    1.5    over
    1.6    the
    1.7    lazy
    1.8    dog
*/

Answer 3

使用IndexOfValue曝光的SortedList方法，结合Linq扩展方法ElementAt(int index)，以便：

string index = list.ElementAt(list.IndexOfValue(value)).Key;//output will be abc

Answer 4

使用SortedList.Values属性获取包含SortedList对象中的值的ICollection对象。

Answer 5

试一试：

SortedList<string, int> list = new SortedList<string, object>();
list.Add("One", 1);
list.Add("Two", 2);                               

int value = (int)list.ElementAt(1).Value;

或......

int value = list.IndexOfKey("One");

从自定义值索引数组中获取数组的索引

5 个答案: