我一直在寻找一种有效的方法来做到这一点,但一直无法找到它,基本上我需要的是给定这个url例如:
http://localhost/mysite/includes/phpThumb.php?src=http://media2.jupix.co.uk/v3/clients/4/properties/795/IMG_795_1_large.jpg&w=592&aoe=1&q=100
我希望能够使用javascript或jquery将src
参数中的URL更改为其他值,这可能吗?
提前致谢。
答案 0 :(得分:110)
以下解决方案结合了其他答案并处理了一些特殊情况:
?
字符\b
确保以paramName结尾的另一个参数不匹配解决方案:
function replaceUrlParam(url, paramName, paramValue)
{
if (paramValue == null) {
paramValue = '';
}
var pattern = new RegExp('\\b('+paramName+'=).*?(&|#|$)');
if (url.search(pattern)>=0) {
return url.replace(pattern,'$1' + paramValue + '$2');
}
url = url.replace(/[?#]$/,'');
return url + (url.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue;
}
已知限制:
答案 1 :(得分:48)
这不是一个更好的解决方案吗?
var text = 'http://localhost/mysite/includes/phpThumb.php?src=http://media2.jupix.co.uk/v3/clients/4/properties/795/IMG_795_1_large.jpg&w=592&aoe=1&q=100';
var newSrc = 'www.google.com';
var newText = text.replace(/(src=).*?(&)/,'$1' + newSrc + '$2');
编辑:
在代码中添加了一些清晰度,并在结果链接中保留了“src”
$1
代表()
中的第一部分(即)src=
,$2
代表()
中的第二部分(即){{1} },这表示您要更改&
和src
之间的值。更清楚,它应该是这样的:
&
替换所有发生的ADD-ON:
如果您有多个具有相同名称的参数,则可以附加到regex全局标志,如此src='changed value'& // this is to be replaced with your original url
,这将替换那些具有相同名称的参数的所有值。
答案 2 :(得分:15)
Javascript现在提供了一个非常有用的功能来处理url参数:URLSearchParams
var searchParams = new URLSearchParams(window.location.search);
searchParams.set('src','newSrc')
var newParams = searchParams.toString()
答案 3 :(得分:10)
现在可以使用原生JS
var href = new URL('https://google.com?q=cats');
href.searchParams.set('q', 'dogs');
console.log(href.toString()); // https://google.com/?q=dogs
答案 4 :(得分:6)
这里修改了stenix的代码,它并不完美,但它处理的情况是url中有一个包含提供参数的参数,例如:
/search?searchquery=text and 'query' is provided.
在这种情况下,searchquery参数值已更改。
代码:
function replaceUrlParam(url, paramName, paramValue){
var pattern = new RegExp('(\\?|\\&)('+paramName+'=).*?(&|$)')
var newUrl=url
if(url.search(pattern)>=0){
newUrl = url.replace(pattern,'$1$2' + paramValue + '$3');
}
else{
newUrl = newUrl + (newUrl.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue
}
return newUrl
}
答案 5 :(得分:2)
如果您使用的是非常狭窄且特定的用例,例如将具有字母数字值的给定名称的特定参数替换为某些特殊字符且上限为特定长度限制,则可以尝试这种方法:
urlValue.replace(/\bsrc=[0-9a-zA-Z_@.#+-]{1,50}\b/, 'src=' + newValue);
示例:
let urlValue = 'www.example.com?a=b&src=test-value&p=q';
const newValue = 'sucess';
console.log(urlValue.replace(/\bsrc=[0-9a-zA-Z_@.#+-]{1,50}\b/, 'src=' + newValue));
// output - www.example.com?a=b&src=sucess&p=q
答案 6 :(得分:1)
更新:让它成为一个很好的功能:http://jsfiddle.net/wesbos/KH25r/1/
function swapOutSource(url, newSource) {
params = url.split('&');
var src = params[0].split('=');
params.shift();
src[1] = newSource;
var newUrl = ( src.join('=') + params.join('&'));
return newUrl;
}
然后去吧!
var newUrl = swapOutSource("http://localhost/mysite/includes/phpThumb.php?src=http://media2.jupix.co.uk/v3/clients/4/properties/795/IMG_795_1_large.jpg&w=592&aoe=1&q=100","http://link/to/new.jpg");
console.log(newUrl);
答案 7 :(得分:1)
如果你仔细观察,你会看到两个关于URL的令人惊讶的事情:(1)它们看起来很简单,但细节和极端情况实际上很难,(2)令人惊讶的是,JavaScript并没有为使用它提供完整的API他们更容易。我认为一个成熟的图书馆是为了避免人们自己重新发明轮子或复制一些随机的家伙聪明,但很可能是错误的正则表达式代码片段。也许试试URI.js(http://medialize.github.io/URI.js/)
答案 8 :(得分:1)
在现代浏览器(除IE9及以下版本中的所有浏览器)中,new URL api
现在使我们的生活更加轻松var url = new window.URL(document.location); // fx. http://host.com/endpoint?abc=123
url.searchParams.set("foo", "bar");
console.log(url.toString()); // http://host/endpoint?abc=123&foo=bar
url.searchParams.set("foo", "ooft");
console.log(url.toString()); // http://host/endpoint?abc=123&foo=ooft
答案 9 :(得分:1)
编辑参数 URLSearchParams对象的set方法设置参数的新值。
设置新值后,您可以使用toString()方法获取新的查询字符串。可以将该查询字符串设置为URL对象的search属性的新值。
然后可以使用URL对象的toString()方法检索最终的新URL。
var query_string = url.search;
var search_params = new URLSearchParams(query_string);
// new value of "id" is set to "101"
search_params.set('id', '101');
// change the search property of the main url
url.search = search_params.toString();
// the new url string
var new_url = url.toString();
// output : http://demourl.com/path?id=101&topic=main
console.log(new_url);
来源-https://usefulangle.com/post/81/javascript-change-url-parameters
答案 10 :(得分:0)
// Construct URLSearchParams object instance from current URL querystring.
var queryParams = new URLSearchParams(window.location.search);
// Set new or modify existing parameter value.
queryParams.set("myParam", "myValue");
// Replace current querystring with the new one.
history.replaceState(null, null, "?"+queryParams.toString());
或者,我们可以使用 pushState() 方法创建一个新的,而不是使用 replaceState() 修改当前历史条目:
history.pushState(null, null, "?"+queryParams.toString());
答案 11 :(得分:0)
这样的事情怎么样:
<script>
function changeQueryVariable(keyString, replaceString) {
var query = window.location.search.substring(1);
var vars = query.split("&");
var replaced = false;
for (var i = 0; i < vars.length; i++) {
var pair = vars[i].split("=");
if (pair[0] == keyString) {
vars[i] = pair[0] + "="+ replaceString;
replaced = true;
}
}
if (!replaced) vars.push(keyString + "=" + replaceString);
return vars.join("&");
}
</script>
答案 12 :(得分:0)
这里是用paramVal替换url param的函数
function updateURLParameter(url, param, paramVal){
if(!url.includes('?')){
return url += '?' + param + '=' + paramVal;
}else if(!url.includes(param)){
return url += '&' + param + '=' + paramVal;
}else {
let paramStartIndex = url.search(param);
let paramEndIndex = url.indexOf('&', paramStartIndex);
if (paramEndIndex == -1){
paramEndIndex = url.length;
}
let brands = url.substring(paramStartIndex, paramEndIndex);
return url.replace(brands, param + '=' + paramVal);
}
}
答案 13 :(得分:0)
2020年的答案,因为我缺少自动删除参数的功能,所以:
基于我最喜欢的答案https://stackoverflow.com/a/20420424/6284674: 我结合了以下功能:
null
或''
的值基于答案https://stackoverflow.com/a/25214672/6284674 ,则自动删除 URL参数
(可选)直接在window.location栏中推更新的URL
IE支持,因为它仅使用正则表达式而不使用URLSearchParams
JSfiddle:https://jsfiddle.net/MickV/zxc3b47u/
function replaceUrlParam(url, paramName, paramValue){
if(paramValue == null || paramValue == "")
return url
.replace(new RegExp('[?&]' + paramValue + '=[^&#]*(#.*)?$'), '$1')
.replace(new RegExp('([?&])' + paramValue + '=[^&]*&'), '$1');
url = url.replace(/\?$/,'');
var pattern = new RegExp('\\b('+paramName+'=).*?(&|$)')
if(url.search(pattern)>=0){
return url.replace(pattern,'$1' + paramValue + '$2');
}
return url + (url.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue
}
// Orginal URL (default jsfiddle console URL)
//https://fiddle.jshell.net/_display/?editor_console=true
console.log(replaceUrlParam(window.location.href,'a','2'));
//https://fiddle.jshell.net/_display/?editor_console=true&a=2
console.log(replaceUrlParam(window.location.href,'a',''));
//https://fiddle.jshell.net/_display/?editor_console=true
console.log(replaceUrlParam(window.location.href,'a',3));
//https://fiddle.jshell.net/_display/?editor_console=true&a=3
console.log(replaceUrlParam(window.location.href,'a', null));
//https://fiddle.jshell.net/_display/?editor_console=true&
//Optionally also update the replaced URL in the window location bar
//Note: This does not work in JSfiddle, but it does in a normal browser
function pushUrl(url){
window.history.pushState("", "", replaceUrlParam(window.location.href,'a','2'));
}
pushUrl(replaceUrlParam(window.location.href,'a','2'));
//https://fiddle.jshell.net/_display/?editor_console=true&a=2
pushUrl(replaceUrlParam(window.location.href,'a',''));
//https://fiddle.jshell.net/_display/?editor_console=true
pushUrl(replaceUrlParam(window.location.href,'a',3));
//https://fiddle.jshell.net/_display/?editor_console=true&a=3
pushUrl(replaceUrlParam(window.location.href,'a', null));
//https://fiddle.jshell.net/_display/?editor_console=true&
答案 14 :(得分:0)
没有正则表达式的解决方案,在我眼中寻找的是一个简单的解决方法
这支持端口,哈希参数等。
使用浏览器属性元素作为解析器。
function setUrlParameters(url, parameters) {
var parser = document.createElement('a');
parser.href = url;
url = "";
if (parser.protocol) {
url += parser.protocol + "//";
}
if (parser.host) {
url += parser.host;
}
if (parser.pathname) {
url += parser.pathname;
}
var queryParts = {};
if (parser.search) {
var search = parser.search.substring(1);
var searchParts = search.split("&");
for (var i = 0; i < searchParts.length; i++) {
var searchPart = searchParts[i];
var whitespaceIndex = searchPart.indexOf("=");
if (whitespaceIndex !== -1) {
var key = searchPart.substring(0, whitespaceIndex);
var value = searchPart.substring(whitespaceIndex + 1);
queryParts[key] = value;
} else {
queryParts[searchPart] = false;
}
}
}
var parameterKeys = Object.keys(parameters);
for (var i = 0; i < parameterKeys.length; i++) {
var parameterKey = parameterKeys[i];
queryParts[parameterKey] = parameters[parameterKey];
}
var queryPartKeys = Object.keys(queryParts);
var query = "";
for (var i = 0; i < queryPartKeys.length; i++) {
if (query.length === 0) {
query += "?";
}
if (query.length > 1) {
query += "&";
}
var queryPartKey = queryPartKeys[i];
query += queryPartKey;
if (queryParts[queryPartKey]) {
query += "=";
query += queryParts[queryPartKey];
}
}
url += query;
if (parser.hash) {
url += parser.hash;
}
return url;
}
答案 15 :(得分:0)
我使用以下方法:
返回已删除参数的值
function getUrlParameterAndRemoveParameter(paramName) {
var url = window.location.origin + window.location.pathname;
var s = window.location.search.substring(1);
var pArray = (s == "" ? [] : s.split('&'));
var paramValue = null;
var pArrayNew = [];
for (var i = 0; i < pArray.length; i++) {
var pName = pArray[i].split('=');
if (pName[0] === paramName) {
paramValue = pName[1] === undefined ? true : decodeURIComponent(pName[1]);
}
else {
pArrayNew.push(pArray[i]);
}
}
url += (pArrayNew.length == 0 ? "" : "?" + pArrayNew.join('&'));
window.history.replaceState(window.history.state, document.title, url);
return paramValue;
}
答案 16 :(得分:0)
我有最好的解决方案来替换URL参数。
以下功能会将房间值替换为以下URL中的3。
var newurl = replaceUrlParam('room','3');
history.pushState(null, null, newurl);
function replaceUrlParam(paramName, paramValue){
var url = window.location.href;
if (paramValue == null) {
paramValue = '';
}
var pattern = new RegExp('\\b('+paramName+'=).*?(&|#|$)');
if (url.search(pattern)>=0) {
return url.replace(pattern,'$1' + paramValue + '$2');
}
url = url.replace(/[?#]$/,'');
return url + (url.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue;
}
输出
http://example.com/property/?min=50000&max=60000&room=3&property_type=House
答案 17 :(得分:0)
尝试
var updateQueryStringParam = function (key, value) {
var baseUrl = [location.protocol, '//', location.host, location.pathname].join(''),
urlQueryString = document.location.search,
newParam = key + '=' + value,
params = '?' + newParam;
// If the "search" string exists, then build params from it
if (urlQueryString) {
var updateRegex = new RegExp('([\?&])' + key + '[^&]*');
var removeRegex = new RegExp('([\?&])' + key + '=[^&;]+[&;]?');
if( typeof value == 'undefined' || value == null || value == '' ) { // Remove param if value is empty
params = urlQueryString.replace(removeRegex, "$1");
params = params.replace( /[&;]$/, "" );
} else if (urlQueryString.match(updateRegex) !== null) { // If param exists already, update it
params = urlQueryString.replace(updateRegex, "$1" + newParam);
} else { // Otherwise, add it to end of query string
params = urlQueryString + '&' + newParam;
}
}
// no parameter was set so we don't need the question mark
params = params == '?' ? '' : params;
window.history.replaceState({}, "", baseUrl + params);
};
答案 18 :(得分:0)
除了@stenix,这对我来说非常合适
url = window.location.href;
paramName = 'myparam';
paramValue = $(this).val();
var pattern = new RegExp('('+paramName+'=).*?(&|$)')
var newUrl = url.replace(pattern,'$1' + paramValue + '$2');
var n=url.indexOf(paramName);
alert(n)
if(n == -1){
newUrl = newUrl + (newUrl.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue
}
window.location.href = newUrl;
这里不需要保存“url”变量,只需在当前url中替换