我正在尝试让程序在当前实例中打开一个文件而不是一个新实例,这是我到目前为止所得到的,我从this question得到的。
static class Program
{
static EsfEditorSingleton controller;
[STAThread]
public static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
// Show the main form of the app.
controller = new EsfEditorSingleton();
string[] args = Environment.GetCommandLineArgs();
controller.Run(args);
controller.StartupNextInstance += controller.NextInstanceStartup;
}
}
public class EsfEditorSingleton : WindowsFormsApplicationBase
{
internal EsfEditorSingleton() : base()
{
this.IsSingleInstance = true;
this.MainForm = new EsfEditorForm();
}
public void NextInstanceStartup(object sender, StartupNextInstanceEventArgs e)
{
EsfEditorForm form = (EsfEditorForm)this.MainForm;
string[] args = null;
e.CommandLine.CopyTo(args, 0);
form.mProcessArgs(args);
}
}
更新:以下是上述调用的部分。
public class EsfEditorForm : Form
{
public EsfEditorForm()
{
this.InitializeComponent();
}
protected override void OnLoad(EventArgs e)
{
base.OnLoad(e);
string[] args = Environment.GetCommandLineArgs();
mProcessArgs(args);
}
public void mProcessArgs(string[] args)
{
if (args.Length > 0)
{
for (int i = 0; i < args.Length; i++)
{
if (System.IO.File.Exists(args[i])) { this.OpenFile(args[i]); }
}
}
}
}
当我在VS 2010 Pro(FYI)中点击F5时,它编译并启动,然后在Visual Studio中给出了我的IOException处理错误:
该进程无法访问文件'I:\ Program Files \ Totar \ EFS Editor \ VS - Solution \ bin \ x86 \ Release \ EsfEditor 1.4.8.exe',因为它正由另一个进程使用。
我相信提到的文件是目前正在运行的可执行文件。
栈跟踪:
at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath)
at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy)
at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share)
at System.IO.File.Open(String path, FileMode mode, FileAccess access, FileShare share)
at EsfEditor.Parser.EsfParser..ctor(String filename)
at EsfEditor.Core.EsfObjects.EsfFile..ctor(String filePath)
at EsfEditor.Forms.EsfEditorForm.OpenFile(String filePath)
at EsfEditor.Forms.EsfEditorForm.mProcessArgs(String[] args)
at EsfEditor.Forms.EsfEditorForm.OnLoad(EventArgs e)
at System.Windows.Forms.Form.OnCreateControl()
at System.Windows.Forms.Control.CreateControl(Boolean fIgnoreVisible)
at System.Windows.Forms.Control.CreateControl()
at System.Windows.Forms.Control.WmShowWindow(Message& m)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ContainerControl.WndProc(Message& m)
at System.Windows.Forms.Form.WmShowWindow(Message& m)
at System.Windows.Forms.Form.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.SafeNativeMethods.ShowWindow(HandleRef hWnd, Int32 nCmdShow)
at System.Windows.Forms.Control.SetVisibleCore(Boolean value)
at System.Windows.Forms.Form.SetVisibleCore(Boolean value)
at System.Windows.Forms.Control.set_Visible(Boolean value)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.Run(ApplicationContext context)
at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.OnRun()
at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.DoApplicationModel()
at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.Run(String[] commandLine)
at EsfEditor.Program.Main()
答案 0 :(得分:1)
你不应该跳过mProcessArgs中的第一个参数吗?
public void mProcessArgs(string[] args)
{
if (args.Length > 0)
{
for (int i = **1**; i < args.Length; i++)
{
if (System.IO.File.Exists(args[i])) { this.OpenFile(args[i]); }
}
}
}
答案 1 :(得分:0)
Environment.GetCommandLineArgs()中的第一个参数是正在运行的可执行文件。您需要修改Main方法以传入Environment.GetCommandLineArgs()。跳过(1)到您的controller.Run()方法