Question

我将图像保存到缓存中，然后检索它们。

我将一些url字符串保存到SharedPreferences，然后在活动为Create（）时将它们拉出来。

问题在于我运行此方法..

public void getImagesfromCache(){
        ImageAdapter adapter = new ImageAdapter();

    String[] cachImages = myRemoteImages; //I set the CacheImages String[] here

    try {   
     URL aURL2 = null;
     aURL2 = new URL(cachImages[position]);  //I get a MalformedURLException here 
     URI imageCacheUri = null;


     try {
            imageCacheUri = aURL2.toURI();
        } catch (URISyntaxException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        if(new File(new File(this.getApplicationContext().getCacheDir(), "thumbnails"),"" + imageCacheUri.hashCode()).exists()){
            Log.v("FOUND", "Images found in cache! Now being loaded!");
            String cacheFile = this.getApplicationContext().getCacheDir() +"/thumbnails/"+ imageCacheUri.hashCode();
            ImageView i = new ImageView(this.getApplicationContext());
            FileInputStream fis = null;
            try {
                fis = new FileInputStream(cacheFile);
            } catch (FileNotFoundException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            Bitmap bm = BitmapFactory.decodeStream(fis);

             i.setImageBitmap(bm);
             putBitmapInDiskCache(imageCacheUri, bm);

             Log.v("Loader", "Image saved to cache");

             ((Gallery) findViewById(R.id.gallery))
              .setAdapter(new ImageAdapter(MainMenu.this));
        }

    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

创建活动时，我将每个网址设置为共享偏好中的变量。

        SharedPreferences app_preferences = 
            this.getSharedPreferences("images_urls", MODE_WORLD_READABLE);
    imageUrl = app_preferences.getString("URL1", "Does not exist in preference");
    imageUrl2 = app_preferences.getString("URL2", "Does not exist in cache");
    imageUrl3 = app_preferences.getString("URL3", "Does not exist in preference");
    imageUrl4 = app_preferences.getString("URL4", "Does not exist in preference");

    Log.e("Preference", imageUrl + imageUrl2 + imageUrl3 + imageUrl4);

如你所见，我记录它以确保它拉动的东西。它在调试中显示我最初保存的所有URL。

当从SharePreferences中提取字符串时，我在oncreate中调用getimagesfromCache（），

那么为什么我在那条线上得到malformedURLException？

编辑：这是我用于远程图像的代码....

并且位置..

 int position;

public String [] myRemoteImages = {imageUrl，imageUrl2，imageUrl3，imageUrl4};

我有一个图像适配器......我使用BaseAdapter内部设置位置

    public View getView(int position, View convertView, ViewGroup parent) {
                ImageView i = new ImageView(this.myContext);

                try {

            URL aURL = new URL(myRemoteImages[position]);

编辑：我如何在imageAdapter的getView（）中使用int位置？还是我需要它？

在onCreate（）中使用从SharedPreference中提取的String []时出现MalformedURLException

0 个答案: