我有
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<solid
android:color="#FFFF00" />
<padding android:left="7dp"
android:top="7dp"
android:right="7dp"
android:bottom="7dp" />
</shape>
<TextView
android:background="@drawable/test"
android:layout_height="45dp"
android:layout_width="100dp"
android:text="Moderate"
/>
所以现在我希望这个形状根据我从Web服务调用返回的信息来改变颜色。因此它可能是黄色或绿色或红色或其他任何颜色,具体取决于我从网络电话呼叫中收到的颜色。
如何更改形状的颜色?根据这些信息?
答案 0 :(得分:285)
你可以像这样修改它
GradientDrawable bgShape = (GradientDrawable)btn.getBackground();
bgShape.setColor(Color.BLACK);
答案 1 :(得分:58)
对我来说,它崩溃了,因为getBackground
返回了GradientDrawable
而不是ShapeDrawable
。
所以我修改了它:
((GradientDrawable)someView.getBackground()).setColor(someColor);
答案 2 :(得分:41)
这适用于我,使用初始xml资源:
example.setBackgroundResource(R.drawable.myshape);
GradientDrawable gd = (GradientDrawable) example.getBackground().getCurrent();
gd.setColor(Color.parseColor("#000000"));
gd.setCornerRadii(new float[]{30, 30, 30, 30, 0, 0, 30, 30});
gd.setStroke(2, Color.parseColor("#00FFFF"), 5, 6);
答案 3 :(得分:10)
您可以使用Java构建自己的形状。 我为像Page Controler这样的iPhone做了这个,并用Java绘制形状:
/**
* Builds the active and inactive shapes / drawables for the page control
*/
private void makeShapes() {
activeDrawable = new ShapeDrawable();
inactiveDrawable = new ShapeDrawable();
activeDrawable.setBounds(0, 0, (int) mIndicatorSize,
(int) mIndicatorSize);
inactiveDrawable.setBounds(0, 0, (int) mIndicatorSize,
(int) mIndicatorSize);
int i[] = new int[2];
i[0] = android.R.attr.textColorSecondary;
i[1] = android.R.attr.textColorSecondaryInverse;
TypedArray a = this.getTheme().obtainStyledAttributes(i);
Shape s1 = new OvalShape();
s1.resize(mIndicatorSize, mIndicatorSize);
Shape s2 = new OvalShape();
s2.resize(mIndicatorSize, mIndicatorSize);
((ShapeDrawable) activeDrawable).getPaint().setColor(
a.getColor(0, Color.DKGRAY));
((ShapeDrawable) inactiveDrawable).getPaint().setColor(
a.getColor(1, Color.LTGRAY));
((ShapeDrawable) activeDrawable).setShape(s1);
((ShapeDrawable) inactiveDrawable).setShape(s2);
}
希望这会有所帮助。
Greez Fabian
答案 4 :(得分:5)
LayerDrawable bgDrawable = (LayerDrawable) button.getBackground();
final GradientDrawable shape = (GradientDrawable)
bgDrawable.findDrawableByLayerId(R.id.round_button_shape);
shape.setColor(Color.BLACK);
答案 5 :(得分:5)
也许其他人需要在XML中更改颜色而不需要像我需要的那样创建多个drawable。然后制作一个没有颜色的圆形绘图,然后为ImageView指定backgroundTint。
<强> circle.xml 强>
<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="oval">
</shape>
在您的布局:
中<ImageView
android:layout_width="50dp"
android:layout_height="50dp"
android:background="@drawable/circle"
android:backgroundTint="@color/red"/>
修改强>
此方法有一个bug阻止它在Android Lollipop 5.0(API级别21)上运行。但已在新版本中修复。
答案 6 :(得分:5)
circle.xml(drawable)
<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<solid
android:color="#000"/>
<size
android:width="10dp"
android:height="10dp"/>
</shape>
布局
<ImageView
android:id="@+id/circleColor"
android:layout_width="15dp"
android:layout_height="15dp"
android:textSize="12dp"
android:layout_gravity="center"
android:layout_marginLeft="10dp"
android:background="@drawable/circle"/>
活动
circleColor = (ImageView) view.findViewById(R.id.circleColor);
int color = Color.parseColor("#00FFFF");
((GradientDrawable)circleColor.getBackground()).setColor(color);
答案 7 :(得分:2)
这个解决方案适用于我使用android sdk v19:
//get the image button by id
ImageButton myImg = (ImageButton) findViewById(R.id.some_id);
//get drawable from image button
GradientDrawable drawable = (GradientDrawable) myImg.getDrawable();
//set color as integer
//can use Color.parseColor(color) if color is a string
drawable.setColor(color)
答案 8 :(得分:2)
如果你有这样的imageView:
<ImageView
android:id="@+id/color_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginRight="10dp"
android:src="@drawable/circle_color"/>
给它一个可绘制的形状作为src,你可以使用这段代码来改变形状的颜色:
ImageView iv = (ImageView)findViewById(R.id.color_button);
GradientDrawable bgShape = (GradientDrawable)iv.getDrawable();
bgShape.setColor(Color.BLACK);
答案 9 :(得分:1)
我的形状xml:
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<solid android:color="@android:color/transparent" />
<stroke android:width="0.5dp" android:color="@android:color/holo_green_dark"/>
</shape>
我的活动xml:
<?xml version="1.0" encoding="utf-8"?>
<android.support.design.widget.CoordinatorLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:fitsSystemWindows="true"
tools:context="cn.easydone.test.MainActivity">
<android.support.design.widget.AppBarLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:theme="@style/AppTheme.AppBarOverlay">
<android.support.v7.widget.Toolbar
android:id="@+id/toolbar"
android:layout_width="match_parent"
android:layout_height="?attr/actionBarSize"
android:background="?attr/colorPrimary"
app:popupTheme="@style/AppTheme.PopupOverlay" />
<TextView
android:id="@+id/test_text"
android:background="@drawable/bg_stroke_dynamic_color"
android:padding="20dp"
android:text="asdasdasdasd"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
</android.support.design.widget.AppBarLayout>
<android.support.v7.widget.RecyclerView
android:id="@+id/recycler_view"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="10dp"
android:clipToPadding="false"
app:layout_behavior="@string/appbar_scrolling_view_behavior" />
我的活动java:
TextView testText = (TextView) findViewById(R.id.test_text);
((GradientDrawable)testText.getBackground()).setStroke(10,Color.BLACK);
结果图: result
答案 10 :(得分:0)
我尝试了Ronnie的回答,我的应用程序崩溃了。然后我检查我的drawable xml。它看起来像这样:
<selector >...</selector>
。我改为:(也改变了属性)
<shape> ... </shape>
有效。
对于那些遇到同样问题的人。
答案 11 :(得分:0)
用半径填充形状的最简单方法是:
XML:
<TextView
android:id="@+id/textView"
android:background="@drawable/test"
android:layout_height="45dp"
android:layout_width="100dp"
android:text="Moderate"/>
Java:
(textView.getBackground()).setColorFilter(Color.parseColor("#FFDE03"), PorterDuff.Mode.SRC_IN);
答案 12 :(得分:0)
drawable_rectangle.xml
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<solid android:color="@android:color/transparent" />
<stroke
android:width="1dp"
android:color="#9f9f9f" />
<corners
android:bottomLeftRadius="5dp"
android:bottomRightRadius="5dp"
android:topLeftRadius="5dp"
android:topRightRadius="5dp" />
</shape>
TextView
<androidx.appcompat.widget.AppCompatTextView
android:id="@+id/textView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="@drawable/drawable_rectangle"
android:gravity="center"
android:padding="10dp"
android:text="Status"
android:textColor="@android:color/white"
android:textSize="20sp" />
public static void changeRectangleColor(View view, int color) {
((GradientDrawable) view.getBackground()).setStroke(1, color);
}
changeRectangleColor(textView, ContextCompat.getColor(context, R.color.colorAccent));
答案 13 :(得分:0)
您可以使用绑定适配器(Kotlin)实现此目的。创建一个名为ChangeShapeColor的绑定适配器类,如下所示
@BindingAdapter("shapeColor")
// Method to load shape and set its color
fun loadShape(textView: TextView, color: String) {
// first get the drawable that you created for the shape
val mDrawable = ContextCompat.getDrawable(textView.context,
R.drawable.language_image_bg)
val shape = mDrawable as (GradientDrawable)
// use parse color method to parse #34444 to the int
shape.setColor(Color.parseColor(color))
}
在res / drawable文件夹中创建一个可绘制形状。我已经创建了一个圈子
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="oval" >
<solid android:color="#anyColorCode"/>
<size
android:width="@dimen/dp_16"
android:height="@dimen/dp_16"/>
</shape>
最后将其引用给您的视图
<TextView>
.........
app:shapeColor="@{modelName.colorString}"
</Textview>