编辑回答

Question

    if (fromObject == null) fromObject = primaryTable;
    var id = fromObject+"_"+toObject;
    var tr = $('<tr id="'+id+'"></tr>').appendTo($("#joins"));

    tr.append('<td width=20%><select style="width:100%" type="text" name="from_object" id="from_object" value=""></select></td>');
    tr.append('<td width=20%><select style="width:100%" type="text" name="to_object" id="to_object" value=""></select></td>');
    tr.append('<td width=20%><input style="width:100%" type="text" name="from_column" id="from_column" value="" readonly></td>');
    tr.append('<td width=20%><input style="width:100%" type="text" name="to_column" id="to_column" value="" readonly></td>');
    tr.append('<td width=20%><select style="width:100%" type="text" name="join_type" id="join_type" value=""></select></td>');


    var combo3 = $("select[name=from_object]");

这是我的问题。我经历了多次附加的过程，并留下了许多具有相同名称的选择标签。我想弄清楚如何选择'from_object'。我必须动态地这样做吗？现在combo3总是选择第一个标签。

Answer 1

我不完全理解这个问题。获得第一次使用

$('select[name=from_object]:first').doWhatever():

获取所有用途

$('select[name=from_object]').each(function(){
    $(this).doWhatever();
});

但是从不使用相同的ID两次。

Answer 2

你的html对那些重复的ID无效。我试着立刻解决你要求的问题和重复的ID问题。如果不能直接开箱即可，它应该会给你一个良好的解决方案。

编辑回答

if (fromObject == null) fromObject = primaryTable;
    var id = fromObject+"_"+toObject;
    // don't append to the DOM until the last second, i moved tr.appendTo() to the end
    var uniqueIdIndex = $("tr[id^='"+id+"_tr'").length +1; // get a unique index
// the idea of cloning HTML and appending it takes some getting used to, but makes it easy to change and maintain. don't let it throw you
// all this cloning stuff is to get you some Unique Ids.
        var masterTR = $('<tr id="'+id+'_tr_'+uniqueIdIndex+'"></tr>');
        var masterTD = $('<td width="20%"></td>');
        var masterDD = $('<select type="text" style="width:100%"></select>');
        var masterCI = $('<input style="width:100%" type="text" value="" readonly></input>');
        // grab a default drop down, set the name, ID and value
        var currentInput = masterDD.clone().attr({"name":"from_object","id": id+"_from_object_"+uniqueIdIndex,"value":""});
        var tr = masterTR.clone(); // get a Row
        tr.append( masterTD.clone().append(currentInput) ); // clone a td, append the input, and append that to the row
         // grab a default drop down, set the name, ID and value 
        currentInput = masterDD.clone().attr({"name":"to_object","id": id+"_to_object_"+uniqueIdIndex,"value":""}); 
        tr.append(masterTD.clone().append(currentInput));
        currentInput = masterCI.clone().attr({"name":"from_column","id": id+"_from_column_"+uniqueIdIndex,"value":""});
        tr.append(masterTD.clone().append(currentInput));
        currentInput = masterCI.clone().attr({"name":"to_column","id": id+"_to_column_"+uniqueIdIndex,"value":""});
        tr.append(masterTD.clone().append(currentInput));
        currentInput = masterDD.clone().attr({"name":"join_type","id": id+"_join_type_"+uniqueIdIndex,"value":""});
        tr.append(masterTD.clone().append(currentInput));

            tr.appendTo($("#joins"));
//optionally, find the most recently added from_column "select[name='from_column']"
            var combo3 = $("[id^='"+id+"_from_column]", "#joins").filter(":last");

旧答案

if（fromObject == null）fromObject = primaryTable; var id = fromObject +“_”+ toObject; var tr = $（''）。appendTo（$（“＃join”））;

    tr.append('<td width=20%><select style="width:100%" type="text" name="from_object" id="'+id+'from_object" value=""></select></td>');
    tr.append('<td width=20%><select style="width:100%" type="text" name="to_object" id="'+id+'to_object" value=""></select></td>');
    tr.append('<td width=20%><input style="width:100%" type="text" name="from_column" id="'+id+'from_column" value="" readonly></td>');
    tr.append('<td width=20%><input style="width:100%" type="text" name="to_column" id="'+id+'to_column" value="" readonly></td>');
    tr.append('<td width=20%><select style="width:100%" type="text" name="join_type" id="'+id+'join_type" value=""></select></td>');



    var combo3 = $("#"+id+"from_object");

从具有相同名称的多个标签中选择<select> </select>

2 个答案:

编辑回答

旧答案