我正在尝试使用一个常量的gps监听器,每隔x分钟将其位置(长和lat坐标)发送到Web服务器。在按钮上单击它还会将其位置发送到Web服务器。我知道要获取gps信号,你可以输入寻找位置的频率,但是如何编写一个程序可以获得gps位置并每x分钟发送一次坐标(即使在背景中也没有按下按钮) ?
//点击
LocationManager lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
locationManager.requestLocationUpdates(
LocationManager.GPS_PROVIDER, whatshouldIputhere?, 0, this);
和
public void onLocationChanged(Location location) {
if (location != null) {
double lat = location.getLatitude();
double lng = location.getLongitude();
}
}
答案 0 :(得分:18)
我有这个工作:
private void _getLocation() {
// Get the location manager
LocationManager locationManager = (LocationManager)
getSystemService(LOCATION_SERVICE);
Criteria criteria = new Criteria();
String bestProvider = locationManager.getBestProvider(criteria, false);
Location location = locationManager.getLastKnownLocation(bestProvider);
try {
lat = location.getLatitude();
lon = location.getLongitude();
} catch (NullPointerException e) {
lat = -1.0;
lon = -1.0;
}
}
这很简单。它获得了最佳可用提供商并获得其最后的已知位置。
如果只想使用GPS,请尝试this。
希望有所帮助!
试试这个:
private void _getLocation() {
// Get the location manager
LocationManager locationManager = (LocationManager)
getSystemService(LOCATION_SERVICE);
Criteria criteria = new Criteria();
String bestProvider = locationManager.getBestProvider(criteria, false);
Location location = locationManager.getLastKnownLocation(bestProvider);
LocationListener loc_listener = new LocationListener() {
public void onLocationChanged(Location l) {}
public void onProviderEnabled(String p) {}
public void onProviderDisabled(String p) {}
public void onStatusChanged(String p, int status, Bundle extras) {}
};
locationManager
.requestLocationUpdates(bestProvider, 0, 0, loc_listener);
location = locationManager.getLastKnownLocation(bestProvider);
try {
lat = location.getLatitude();
lon = location.getLongitude();
} catch (NullPointerException e) {
lat = -1.0;
lon = -1.0;
}
}
此代码获取最后一个已知位置,然后请求实际位置。
答案 1 :(得分:3)
一种方法是使用Timer
和TimerTask
Timer timer = new Timer();
timer.scheduleAtFixedRate(new SendLocationTask(), 0, 60000);
class SendLocationTask extends TimerTask{
public abstract void run(){
// send position info here
}
}
答案 2 :(得分:2)
答案 3 :(得分:2)
您可以创建一个将在后台运行的线程,并且每隔x分钟通过调用一个函数来获取实际位置(请注意,您要创建一个获取x,y坐标的函数,因为您将使用该函数按钮点击aswel)。对于您发布的代码:
locationManager.requestUpdates(provider, minTime, minDistance, intent);
这意味着你的应用程序会每隔x分钟向gps模块发送一个请求以获取whatshouldIputhere吗?
祝你好运, Arkde答案 4 :(得分:0)
此代码适用于我(api 17)
try {
if (ContextCompat.checkSelfPermission(this, android.Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED
|| ContextCompat.checkSelfPermission(this, android.Manifest.permission.ACCESS_COARSE_LOCATION) == PackageManager.PERMISSION_GRANTED)
{
LocationManager locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
Location location = locationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
lat = location.getLatitude();
lon = location.getLongitude();
}
}
catch (Exception e){
e.printStackTrace();
}