从socket中读取http post的内容的问题,只有获取头

时间:2011-08-23 03:51:19

标签: java http httpclient

服务器

 public void HandleConnection(Socket socket) {
    OutputStream out = socket.getOutputStream();
    InputStream in = socket.getInputStream();
              BufferedReader br = new BufferedReader(new InputStreamReader(in));
              String strLine;
              try {
                while ((strLine = br.readLine()) != null)   {
                  System.out.println (strLine);
                  }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

客户端

public void httpPostTest() {
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://192.168.0.2:8080/");

        try {
            httppost.setEntity(new StringEntity("test"));
            HttpResponse response = httpclient.execute(httppost);
        } catch (ClientProtocolException e) {
         e.printStackTrace();
        } catch (IOException e) {
         e.printStackTrace();
        }

    }

对此有何想法?这就是我回来的全部内容,只是标题:

POST / HTTP/1.1
Content-Length: 4
Content-Type: text/plain; charset=ISO-8859-1
Host: 192.168.0.2:8080
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.1.2 (java 1.5)




public String readLine(InputStream inputStream) {
        StringWriter writer = new StringWriter();
        try {
            IOUtils.copy(inputStream, writer, "ASCII");
        } catch (IOException e) {
            e.printStackTrace();
        }
        String theString = writer.toString();
        return theString.trim();
    }

2 个答案:

答案 0 :(得分:1)

根据我的理解,做了一些阅读之后,BufferedReader是一种从http post读取inputStreams的坏方法。我所经历的是,发布帖子的客户端会挂起,所以每个帖子上的连接处理程序线程是什么,当我杀死客户端时,服务器会停止挂起,我会看到消息体。根据我在互联网上收集的信息,读取输入流的最佳方法是逐字节逐步执行,并在字节总和==内容长度值后退出循环。

那就是说,我打算使用Apache HTTPCore来处理这个,因为这似乎是一个更好的解决方案

答案 1 :(得分:0)

值得一提的是,如果有人像我一样来到这里,这就是我写的

InputStream stream = socket.getInputStream();

byte[] b = new byte[1024];
while(stream.read(b) > 0 && !socket.isInputShutdown()) {
    System.out.println(new String(b));
    b = null;
    b = new byte[1024];
}