我根本就不明白这一点。我找到的是一些论坛帖子，上面写着“我不知道如何解决这个问题”。我开始了一个简单的观点。然后我添加了ASIHTTPRequest，使用对php脚本的请求调用与数据库进行通信。我必须在编译之前添加Reachability.h。当我真的试图运行它时，我得到的只是模拟器上的空白屏幕，以及主要的XCode中的SIGABRT错误。
这是输出：
GNU gdb 6.3.50-20050815 (Apple version gdb-1518) (Sat Feb 12 02:52:12 UTC 2011)
Copyright 2004 Free Software Foundation, Inc.
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This GDB was configured as "x86_64-apple-darwin".sharedlibrary apply-load-rules all
Attaching to process 4930.
2011-08-22 21:47:15.996 ViewInfo[4930:207] -[ViewInfoViewController tableView:numberOfRowsInSection:]: unrecognized selector sent to instance 0x4c23b80
2011-08-22 21:47:15.999 ViewInfo[4930:207] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[ViewInfoViewController tableView:numberOfRowsInSection:]: unrecognized selector sent to instance 0x4c23b80'
*** Call stack at first throw:
(
0 CoreFoundation 0x010d05a9 __exceptionPreprocess + 185
1 libobjc.A.dylib 0x01224313 objc_exception_throw + 44
2 CoreFoundation 0x010d20bb -[NSObject(NSObject) doesNotRecognizeSelector:] + 187
3 CoreFoundation 0x01041966 ___forwarding___ + 966
4 CoreFoundation 0x01041522 _CF_forwarding_prep_0 + 50
5 UIKit 0x007792b7 -[UISectionRowData refreshWithSection:tableView:tableViewRowData:] + 1834
6 UIKit 0x00776d88 -[UITableViewRowData numberOfRows] + 108
7 UIKit 0x0062a677 -[UITableView noteNumberOfRowsChanged] + 132
8 UIKit 0x00637708 -[UITableView reloadData] + 773
9 UIKit 0x00634844 -[UITableView layoutSubviews] + 42
10 QuartzCore 0x01ed6a5a -[CALayer layoutSublayers] + 181
11 QuartzCore 0x01ed8ddc CALayerLayoutIfNeeded + 220
12 QuartzCore 0x01e7e0b4 _ZN2CA7Context18commit_transactionEPNS_11TransactionE + 310
13 QuartzCore 0x01e7f294 _ZN2CA11Transaction6commitEv + 292
14 UIKit 0x005be9c9 -[UIApplication _reportAppLaunchFinished] + 39
15 UIKit 0x005bee83 -[UIApplication _runWithURL:payload:launchOrientation:statusBarStyle:statusBarHidden:] + 690
16 UIKit 0x005c9617 -[UIApplication handleEvent:withNewEvent:] + 1533
17 UIKit 0x005c1abf -[UIApplication sendEvent:] + 71
18 UIKit 0x005c6f2e _UIApplicationHandleEvent + 7576
19 GraphicsServices 0x0188e992 PurpleEventCallback + 1550
20 CoreFoundation 0x010b1944 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE1_PERFORM_FUNCTION__ + 52
21 CoreFoundation 0x01011cf7 __CFRunLoopDoSource1 + 215
22 CoreFoundation 0x0100ef83 __CFRunLoopRun + 979
23 CoreFoundation 0x0100e840 CFRunLoopRunSpecific + 208
24 CoreFoundation 0x0100e761 CFRunLoopRunInMode + 97
25 UIKit 0x005be7d2 -[UIApplication _run] + 623
26 UIKit 0x005cac93 UIApplicationMain + 1160
27 ViewInfo 0x000020d9 main + 121
28 ViewInfo 0x00002055 start + 53
)
terminate called after throwing an instance of 'NSException'
Current language: auto; currently objective-c
(gdb)
答案 0 :(得分：1)
您确定要复制正确的输出吗？粘贴的输出显示您添加了一个对象作为UITableViewController的委托，但没有实现强制方法：
- [ViewInfoViewController tableView：numberOfRowsInSection：]：
除此之外，还有缺乏帮助你的代码，我唯一能想到的就是你没有添加the required Frameworks for ASIHTTP，或者你安装了错误的可达性（ASI带有它自己的可达性） ，在另一个文件夹中，它与Apple的Reachability不同，顺便说一下。
答案 1 :(得分：0)
ViewInfoViewController几乎肯定不是UITableViewController（并且不符合<UITableViewDataSource>）。我怀疑它是UIViewController。在任何情况下，正如Nyan指出的那样，ViewInfoViewController没有按照要求执行tableView:numberOfRowsInSection:，或者您已将tableview的datasource连接到错误的对象，并不意味着连线ViewInfoViewController。