如何让UILabel响应点击？

Question

我发现我可以比UITextField更快地创建UILabel，并且我计划在大多数时间使用UILabel来处理我的数据显示应用程序。

总而言之，我希望让用户点击UILabel并让我的回调响应。这可能吗？

感谢。

Answer 1

您可以向UILabel添加UITapGestureRecognizer实例。

例如：

UITapGestureRecognizer *tapGestureRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(labelTapped)];
tapGestureRecognizer.numberOfTapsRequired = 1;
[myLabel addGestureRecognizer:tapGestureRecognizer];
myLabel.userInteractionEnabled = YES;

Answer 2

如果您正在使用故事板，则可以在故事板中执行此整个过程而无需其他代码。在故事板上添加标签，然后在标签上添加一个点击手势。在“实用工具”窗格中，确保＆＃34;启用用户交互＆＃34;检查标签。从点击手势（在故事板中视图控制器的底部），按住Ctrl键并单击并拖动到ViewController.h文件并创建一个Action。然后在ViewController.m文件中实现该操作。

Answer 3

Swift 3.0

初始化tempLabel

的手势

tempLabel?.text = "Label"
let tapAction = UITapGestureRecognizer(target: self, action: #selector(self.actionTapped(_:)))
tempLabel?.isUserInteractionEnabled = true
tempLabel?.addGestureRecognizer(tapAction)

动作接收器

func actionTapped(_ sender: UITapGestureRecognizer) {
    // code here
}

 

Swift 4.0

初始化tempLabel

的手势

tempLabel?.text = "Label"
let tapAction = UITapGestureRecognizer(target: self, action:@selector(actionTapped(_:)))
tempLabel?.isUserInteractionEnabled = true
tempLabel?.addGestureRecognizer(tapAction)

动作接收器

func actionTapped(_ sender: UITapGestureRecognizer) {
    // code here
}

 

Answer 4

Swift 2.0：

我正在添加一个nsmutable字符串作为sampleLabel的文本，启用用户交互，添加点击手势并触发方法。

override func viewDidLoad() {
    super.viewDidLoad()

    let newsString: NSMutableAttributedString = NSMutableAttributedString(string: "Tap here to read the latest Football News.")
    newsString.addAttributes([NSUnderlineStyleAttributeName: NSUnderlineStyle.StyleDouble.rawValue], range: NSMakeRange(4, 4))
    sampleLabel.attributedText = newsString.copy() as? NSAttributedString

    let tapGesture: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: "tapResponse:")
    tapGesture.numberOfTapsRequired = 1
    sampleLabel.userInteractionEnabled =  true
    sampleLabel.addGestureRecognizer(tapGesture)

}
func tapResponse(recognizer: UITapGestureRecognizer) {
    print("tap")
}

Answer 5

您可以改用UIButton并将文本设置为您想要的内容。如果您不想

，按钮不必看起来像按钮

Answer 6

在UILable上添加点按手势

UITapGestureRecognizer *tapAction = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(lblClick:)];
tapAction.delegate =self;
tapAction.numberOfTapsRequired = 1;

//Enable the lable UserIntraction
lblAction.userInteractionEnabled = YES;
[lblAction addGestureRecognizer:tapAction];   

并评估选择方法

- (void)lblClick:(UITapGestureRecognizer *)tapGesture {

}

注意：在.h文件中添加UIGestureRecognizerDelegate

Answer 7

Swift版本： var tapGesture : UITapGestureRecognizer = UITapGestureRecognizer()

然后在viewDidLoad()内添加：

  let yourLbl=UILabel(frame: CGRectMake(x,y,width,height)) as UILabel!

    yourLbl.text = "SignUp"
    tapGesture.numberOfTapsRequired = 1
    yourLbl.addGestureRecognizer(tapGesture)
    yourLbl.userInteractionEnabled = true
    tapGesture.addTarget(self, action: "yourLblTapped:")

Answer 8

如果您想在按钮中使用多行文字，请创建一个带有多行文字的UILabel，并将其作为子视图添加到您的按钮中。

例如：

yourLabel=[Uilabel alloc]init];
yourLabel.frame=yourButtom.Frame;//(frame size should be equal to your button's frame)
[yourButton addSubView:yourLabel]

Answer 9

来自Alvin George的Swift 3

override func viewDidLoad() {
    super.viewDidLoad()
    let newsString: NSMutableAttributedString = NSMutableAttributedString(string: "Tap here to read the latest Football News.")
    newsString.addAttributes([NSUnderlineStyleAttributeName: NSUnderlineStyle.styleDouble.rawValue], range: NSMakeRange(4, 4))
    sampleLabel.attributedText = newsString.copy() as? NSAttributedString

    let tapGesture: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(ViewController.tapResponse))
    tapGesture.numberOfTapsRequired = 1
    sampleLabel.isUserInteractionEnabled =  true
    sampleLabel.addGestureRecognizer(tapGesture)
}

func tapResponse(recognizer: UITapGestureRecognizer) {
    print("tap")
}

Answer 10

Swift版看起来像这样：

func addGestureRecognizerLabel(){
    //Create a instance, in this case I used UITapGestureRecognizer,
    //in the docs you can see all kinds of gestures
    let gestureRecognizer = UITapGestureRecognizer()

    //Gesture configuration
    gestureRecognizer.numberOfTapsRequired = 1
    gestureRecognizer.numberOfTouchesRequired = 1
    /*Add the target (You can use UITapGestureRecognizer's init() for this)
    This method receives two arguments, a target(in this case is my ViewController) 
    and the callback, or function that you want to invoke when the user tap it view)*/
    gestureRecognizer.addTarget(self, action: "showDatePicker")

    //Add this gesture to your view, and "turn on" user interaction
    dateLabel.addGestureRecognizer(gestureRecognizer)
    dateLabel.userInteractionEnabled = true
}

//How you can see, this function is my "callback"
func showDatePicker(){
    //Your code here
    print("Hi, was clicked")
}

//To end just invoke to addGestureRecognizerLabel() when
//your viewDidLoad() method is called

override func viewDidLoad() {
    super.viewDidLoad()
    addGestureRecognizerLabel()
}

Answer 11

我个人更喜欢为UILabel编写扩展的方法。这就是我用的。

import UIKit

extension UILabel {
    /**
     * A map of actions, mapped as [ instanceIdentifier : action ].
     */
    private static var _tapHandlers = [String:(()->Void)]()

    /**
     * Retrieve the address for this UILabel as a String.
     */
    private func getAddressAsString() -> String {
        let addr = Unmanaged.passUnretained(self).toOpaque()
        return "\(addr)"
    }

    /**
     * Set the on tapped event for the label
     */
    func setOnTapped(_ handler: @escaping (()->Void)) {
        UILabel._tapHandlers[getAddressAsString()] = handler
        let gr = UITapGestureRecognizer(target: self, action: #selector(onTapped))
        gr.numberOfTapsRequired = 1
        self.addGestureRecognizer(gr)
        self.isUserInteractionEnabled = true
    }

    /**
     * Handle the tap event.
     */
    @objc private func onTapped() {
        UILabel._tapHandlers[self.getAddressAsString()]?()
    }
}

然后，您可以在任何UILabel实例中使用它：

myLabel.setOnTapped {
    // do something
}

我相信这可能会导致一些内存泄漏，但是我还没有确定如何最好地解决它们。

Answer 12

这在 Xcode 12和Swift 5

中效果很好

let tapAction = UITapGestureRecognizer(target: self,action:#selector(actionTapped(_:)))

userLabel?.isUserInteractionEnabled = true

userLabel?.addGestureRecognizer(tapAction)

以及类似-

的动作方法

@objc func actionTapped(_ sender: UITapGestureRecognizer) {
        print("tapped")
    }