Question

以下代码：

$zip = new ZipArchive();

if ($zip->open('./archive.zip', ZIPARCHIVE::CREATE) !== TRUE) {
    die ("Could not open archive");
}

$iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator("./folder/"));

foreach ($iterator as $key => $value) {
  try {
    $zip->addFile(realpath($key), $key);
    echo "'$key' successfully added.\n";
  } catch (Exception $e) {
    echo "ERROR: Could not add the file '$key': $e\n";
  }
}

$zip->close();

如果您尝试迭代的子文件夹中的文件太多，则会引发以下异常：

Uncaught exception 'UnexpectedValueException' with message 'RecursiveDirectoryIterator::__construct(./some/path/): failed to open dir: Too many open files' in /some/other/path/zip.php:24
Stack trace:
#0 [internal function]: RecursiveDirectoryIterator->__construct('./some/path/')
#1 /some/other/path/zip.php(24): RecursiveDirectoryIterator->getChildren()
#2 {main}
thrown in /some/other/path/zip.php on line 24

如何在不遇到此异常的情况下成功迭代大量文件夹和文件？

Answer 1

只需将迭代器转换为具有iterator_to_array函数的数组，您似乎可以根据需要迭代任意数量的文件：

$iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator("./folder/"));
$files = iterator_to_array($iterator, true);

// iterate over the directory
// add each file found to the archive
foreach ($files as $key => $value) {
  try {
    $zip->addFile(realpath($key), $key);
    echo "'$key' successfully added.\n";
  } catch (Exception $e) {
    echo "ERROR: Could not add the file '$key': $e\n";
  }
}

RecursiveDirectoryIterator对“打开的文件太多”抛出UnexpectedValueException

1 个答案: